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Vilka [71]
3 years ago
13

Please answer!! will give brainliest!

Mathematics
2 answers:
Elza [17]3 years ago
4 0
Sorry I don’t know about that
Eva8 [605]3 years ago
3 0

Answer:

Q1=38

Q3=88

IQR=50

Step-by-step explanation:

You might be interested in
4- A manufacturing process produces items whose weights are normally distributed. It is known that 22.57% of all the items produ
galben [10]

Answer:

\\ \mu = 118\;grams\;and\;\sigma=30\;grams

Step-by-step explanation:

We need to use z-scores and a standard normal table to find the values that corresponds to the probabilities given, and then to solve a system of equations to find \\ \mu\;and\;\sigma.

<h3>First Case: items from 100 grams to the mean</h3>

For finding probabilities that corresponds to z-scores, we are going to use here a <u>Standard Normal Table </u><u><em>for cumulative probabilities from the mean </em></u><em>(Standard normal table. Cumulative from the mean (0 to Z), 2020, in Wikipedia) </em>that is, the "probability that a statistic is between 0 (the mean) and Z".

A value of a z-score for the probability P(100<x<mean) = 22.57% = 0.2257 corresponds to a value of z-score = 0.6, that is, the value is 0.6 standard deviations from the mean. Since this value is <em>below the mean</em> ("the items produced weigh between 100 grams up to the mean"), then the z-score is negative.

Then

\\ z = -0.6\;and\;z = \frac{x-\mu}{\sigma}

\\ -0.6 = \frac{100-\mu}{\sigma} (1)

<h3>Second Case: items from the mean up to 190 grams</h3>

We can apply the same procedure as before. A value of a z-score for the probability P(mean<x<190) = 49.18% = 0.4918 corresponds to a value of z-score = 2.4, which is positive since it is after the mean.

Then

\\ z =2.4\;and\; z = \frac{x-\mu}{\sigma}

\\ 2.4 = \frac{190-\mu}{\sigma} (2)

<h3>Solving a system of equations for values of the mean and standard deviation</h3>

Having equations (1) and (2), we can form a system of two equations and two unknowns values:

\\ -0.6 = \frac{100-\mu}{\sigma} (1)

\\ 2.4 = \frac{190-\mu}{\sigma} (2)

Rearranging these two equations:

\\ -0.6*\sigma = 100-\mu (1)

\\ 2.4*\sigma = 190-\mu (2)

To solve this system of equations, we can multiply (1) by -1, and them sum the two resulting equation:

\\ 0.6*\sigma = -100+\mu (1)

\\ 2.4*\sigma = 190-\mu (2)

Summing both equations, we obtain the following equation:

\\ 3.0*\sigma = 90

Then

\\ \sigma = \frac{90}{3.0} = 30

To find the value of the mean, we need to substitute the value obtained for the standard deviation in equation (2):

\\ 2.4*30 = 190-\mu (2)

\\ 2.4*30 - 190 = -\mu

\\ -2.4*30 + 190 = \mu

\\ \mu = 118

7 0
2 years ago
Help please urgenttt
stiv31 [10]

Answer:

its a

Step-by-step explanation:

3 0
3 years ago
Factorise<br><img src="https://tex.z-dn.net/?f=9x2%20-%20m" id="TexFormula1" title="9x2 - m" alt="9x2 - m" align="absmiddle" cla
kvv77 [185]
It is m/2 - 3/2 = (m + 3) · (m - 3)
5 0
3 years ago
Read 2 more answers
Find the exact value of cos 120° in simplest form with a rational<br> denominator.
IRINA_888 [86]

Given:

cos 120°

To find:

The exact value of cos 120° in simplest form with a rational  denominator.

Solution:

We have,

\cos 120^\circ

It can be written as

\cos 120^\circ=\cos (90^\circ+30^\circ)

\cos 120^\circ=-\sin 30^\circ             [\because \cos (90^\circ-\theta)=-\sin \theta]

\cos 120^\circ=-\left(\dfrac{1}{2}\right)             [\because \sin 30^\circ=\dfrac{1}{2}]

\cos 120^\circ=-\dfrac{1}{2}

Therefore, the exact value of cos 120° is -\dfrac{1}{2}.

7 0
2 years ago
Line JK passes through points J(–4, –5) and K(–6, 3). If the equation of the line is written in slope-intercept form, y = mx + b
4vir4ik [10]
The value of "b" is the y-intercept.

In order to figure out slope-intercept form you need 1 coordinate and the slope.
1) Find the slope, using the 2-point slope formula: "m= y2-y1 / x2-x1".
   ex. m= -5 - 3 / -4 - -6   (simplify)--->   m= -4

2) Fill in the blanks for point-slope formula: "y - y1 = m (x - x1)"
(choose one coordinate, it doesn't matter which one)
   ex. y - -5 = -4 (x - -4)

3) Then use basic algebra to simplify.


7 0
2 years ago
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