4/52
then u would divide both numbers by 4 and get
1/13
Answer:
10%
Step-by-step explanation:
Answer:
Please like this i need pointgs
Step-by-step explanation:
the add 229129802032s3 9230
To find the z-score for a weight of 196 oz., use

A table for the cumulative distribution function for the normal distribution (see picture) gives the area 0.9772 BELOW the z-score z = 2. Carl is wondering about the percentage of boxes with weights ABOVE z = 2. The total area under the normal curve is 1, so subtract .9772 from 1.0000.
1.0000 - .9772 = 0.0228, so about 2.3% of the boxes will weigh more than 196 oz.
This is mathXL right I know it exactly