Parsecs and arcseconds is your answer
We first write the chemical equation:
2HgO → 2Hg + O₂
Next, we calculate the moles of HgO present:
moles = 3 / 216.59
moles = 0.014
Each mole of oxygen gas needs 2 moles of HgO to be produced.
Theoretical moles of oxygen gas produced = 0.014 / 2
= 0.007
Theoretical mass of oxygen = 0.007 x 32 = 0.224 grams
Percentage yield = actual yield / theoretical yield x 100
= 0.195 / 0.224 x 100
= 87.0%
Answer:
50 miles per hour
Explanation:
To find the average speed per hour you have to find the unit rate so 100/2 which is 50. So 50 miles per hour.
Answer:
P is the limiting reagent
Explanation:
P = phosphorus = 30.97g/mol
Cl2 = Chlorine = 70.91g/mol
PCl3 = Phosphorus Trichloride = 137.33g/mol
P + Cl2 = PCl3
Left Side
P = 1
Cl = 2
Right Side
P = 1
Cl = 3
So equation needs to be balanced first
2P + 3Cl = 2PCl3
Left Side
P = 2
Cl = 6
Right Side
P = 2
Cl = 6
That's better.
Ok so we have 12.39g of P so we have 0.4 moles of it
We then have 52.54g of Cl so we have 0.74 moles of it
For every P we need 1.5 Cl so we have an excess of Cl