All categories

3 years ago

How many grams are equivalent to 1.80 x 10^-4 tons? (English tons)

Chemistry

1 answer:

konstantin123 [22]3 years ago

8 0

Answer:

163.44 g

Explanation:

We know that one ton is equal to 2000 lbs and one lb is equal to 454 grams.

Solution:

1.80 × 10∧-4 ton× 2000 lb/ton× 454 g/lb

1.80 × 10∧-4 ton× 2× 10³lb/ton× 454 g/lb

1634.4 g/ 10 = 163.44 g

You might be interested in

Find the percentage composition of a compound that contains 1.94 g of carbon, 0.48 g of hydrogen, and 2.58 g of sulfur.

Svetradugi [14.3K]

Answer : The percentage composition of carbon, hydrogen and sulfur in a compound is, 38.8 %, 9.6 % and 51.6 % respectively.

Explanation :

To calculate the percentage composition of element in sample, we use the equation:

$\%\text{ composition of element}=\frac{\text{Mass of element}}{\text{Mass of sample}}\times 100$

Given:

Mass of carbon = 1.94 g

Mass of hydrogen = 0.48 g

Mass of sulfur = 2.58 g

First we have to calculate the mass of sample.

Mass of sample = Mass of carbon + Mass of hydrogen + Mass of sulfur

Mass of sample = 1.94 + 0.48 + 2.58 = 5.0 g

Now we have to calculate the percentage composition of a compound.

$\%\text{ composition of carbon}=\frac{1.94g}{5.0g}\times 100=38.8\%$

$\%\text{ composition of hydrogen}=\frac{0.48g}{5.0g}\times 100=9.6\%$

$\%\text{ composition of sulfur}=\frac{2.58g}{5.0g}\times 100=51.6\%$

Hence, the percentage composition of carbon, hydrogen and sulfur in a compound is, 38.8 %, 9.6 % and 51.6 % respectively.

3 0

3 years ago

Current is described as

mrs_skeptik [129]

The answer is B the flow of electrons through a substance

3 0

3 years ago

A gas occupies a volume of 85.0 liters at a pressure of 2.24 atm and a temperature of 22.5 degrees celsius. How many moles of ga

White raven [17]

Answer:

n = 7.86 mol

Explanation:

This question can be solved using the ideal gas law of PV = nRT.

Temperature must be in K, so we will convert 22.5C to 295 K ( Kelvin = C + 273).

R is the ideal gas constant of 0.0821.

(2.24atm)(85.0L) = n(0.0821)(295K)

Isolate n to get:

n = (2.24atm)(85.0L)/(0.0821)(295K)

n = 7.86 mol

8 0

3 years ago

Write the name for NaCl

neonofarm [45]

The name for NaCl is Sodium chloride

<h3>Salt and it's examples.</h3>

Salt is defined as the chemical compound that contains both a positively charged cation.and negatively charged anion.

It is formed by the reaction of acid and base is a neutralisation reaction.

Examples of salt include:

Sodium Chloride or Common Salt (NaCl)

Sodium Hydroxide (NaOH)

Sodium Carbonate or Washing Soda (Na2CO3.10H2O)

Baking Soda or Sodium Bi-carbonate (NaHCO3)

Bleaching Powder or Calcium Hypochlorite.

Therefore another name for salt is common salt.

Learn more about salt here:

brainly.com/question/13655717

8 0

2 years ago

Calculate the ph of a solution containing 0.0451 m potassium hydrogen tartrate and 0.028 m dipotassium tartrate. The ka values f

Marina86 [1]

Given buffer:

potassium hydrogen tartrate/dipotassium tartrate (KHC4H4O6/K2C4H4O6 )

[KHC4H4O6] = 0.0451 M

[K2C4H4O6] = 0.028 M

Ka1 = 9.2 *10^-4

Ka2 = 4.31*10^-5

Based on Henderson-Hasselbalch equation;

pH = pKa + log [conjugate base]/[acid]

where pka = -logKa

In this case we will use the ka corresponding to the deprotonation of the second proton i.e. ka2

pH = -log Ka2 + log [K2C4H4O6]/[KHC4H4O6]

= -log (4.31*10^-5) + log [0.0451]/[0.028]

pH = 4.15

4 0

3 years ago