Differentiating an integral removes the integral.
f(x) = integral of dt/sqrt(t^3 + 2)
f'(x) = 1/sqrt(x^3 + 2)
f'(1) = 1/sqrt(1^3 + 2)
f'(1) = 1/sqrt(3) = sqrt(3)/3.
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Hey there!
<u>Constant terms</u> are the terms where no variables are there (only the constant, i.e, the number). So, here the term <em><u>8</u></em><em><u> </u></em><em><u> </u></em>is the constant term because it doesn't have any variables.
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Given two points A(x₁,y₁) and B(x₂,y₂) the distance betwen these points will be:
dist(A,B)=√[(x₂-x₁)²+(y₂-y₁)²].
We have these points: A(0,0) and B(6,3); its distance will be:
dist(A,B)=√[(6-0)²+(3-0)²]
=√(6²+3²)
=√(36+9)
=√45 ≈ 6.71
Answer: D. 6.71 units.
Answer:
36k
Step-by-step explanation:
36k = 2² × 3² × k
144k = 2^4 × 3² × k
GCF = 2² × 3² × k
GFC = 36k
