Ask question

Ask question

All categories

3 years ago

9

Paula bought a ski jacket on sale for $5 less than half its original price. She paid $85 for the jacket. What was the original p

rice?

1 answer:

NikAS [45]3 years ago

3 0

Answer:

85+5=90x2=$180

Step-by-step explanation:

You might be interested in

Find the cost of twelve $1,000 bonds, at a quotient of 84.50

Natali [406]

Wouldn't you have to multiply 12 time 1,000 then that by 84.50? Hope this helps

8 0

3 years ago

Approximate the area between the xxx-axis and h(x) = \dfrac{1}{7-x}h(x)= 7−x 1 h, (, x, ), equals, start fraction, 1, divided

tiny-mole [99]

Answer:

$\dfrac{47}{60}$ sq. units.

Step-by-step explanation:

The given function is

$h(x)=\dfrac{1}{7-x}$

We need to find the area between x-axis and the given function from x=2 to x=5.

Left Riemann sum formula of area:

$Area=\sum_{n=0}^{N-1}f(x_n)(\Delta x_n)$

For given question,

$Area=\sum_{n=2}^{5-1}f(x_n)(\Delta x_n)$

$Area=\sum_{n=2}^{4}f(x_n)(\Delta x_n)$

$Area=f(x_2)(3-2)+f(x_3)(4-3)+f(x_4)(5-4)$

Now,

$Area=\dfrac{1}{7-2}\times (1)+\dfrac{1}{7-3}\times (1)+\dfrac{1}{7-4}\times (1)$

$Area=\dfrac{1}{5}+\dfrac{1}{4}+\dfrac{1}{3}$

$Area=\dfrac{12+15+20}{60}$

$Area=\dfrac{47}{60}$

Therefore, the required area is $\dfrac{47}{60}$ sq. units.

5 0

3 years ago

Is (6,3) a solution to this system of equations y=3x - 3 3x - y =3

aleksandr82 [10.1K]

Answer:

It is not a solution

Step-by-step explanation:

Plug the point into the equations and check to see if they are true

y=3x - 3

3 = 3(6) -3

3 = 18-3

3 = 15

False

We do not need to check the other equation since this is false

3 0

3 years ago

Finding missing angles in triangles worksheet answers house

sdas [7]

Step-by-step explanation:

What exactly are you looking for?

5 0

2 years ago

Q(a+1) - 2q(a) if q(x) = x²+3x+4

siniylev [52]

$q(x) = {x}^{2} + 3x + 4$

_________________________________

Step(1)

To find q(a) we just need to put a instead of x in q(x) function.

Let's do it...

$q(a) = {a}^{2} + 3a + 4$

Multiply sides by -2 :

$- 2q(a) = - 2( {a}^{2} + 3a + 4)$

$- 2q(a) = - 2 {a}^{2} - 6a - 8$

_________________________________

Step (2)

To find q(a+1) we just need to put a+1 instead of x in q(x) function.

Let's do it...

$q(a + 1) = ({a + 1})^{2} + 3(a + 1) + 4 \\$

$q(a + 1) = {a}^{2} + 2a + 1 + 3a + 3 + 4 \\$

$q(a + 1) = {a}^{2} + 5a + 8$

_________________________________

Step (3)

$q(a + 1) - 2q(a) =$

${a}^{2} + 5a + 8 - 2 {a}^{2} - 6a - 8 = \\$

$- {a}^{2} - a = - a(a + 1)$

And we're done.

Thanks for watching buddy good luck.

♥️♥️♥️♥️♥️

8 0

3 years ago