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nlexa [21]
2 years ago
9

4. Kameron bought 22.3 gallons of gasoline. There are approximately 3.8 liters in 1 gallon of

Mathematics
1 answer:
Lesechka [4]2 years ago
4 0

Answer:

84.74 L

Step-by-step explanation:

22.3*3.8

estimate 22 gal *4 L/gal = 88L

so 84.74

To calculate,

22.3*3.8 = 84.74

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Ricardo lost 6 golf balls while playing yesterday . He bought a box of 12 golf balls, then lost 4 on the course today. He now ha
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He had 6 golf balls to begin with
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2 years ago
Which points are solutions to the system of inequalities? Select ALL that apply.
ZanzabumX [31]

Answer:

0,0

2,-1

-2,4

Step-by-step explanation:

3 0
3 years ago
What are the real or imaginary solutions of the polynomial equation x*4-25=0​
Paul [167]

Hello from MrBillDoesMath!

Answer:

Solutions: x = +\- 5i or x = +\- sqrt(5)


Discussion:

Factor x^4 - 25:

x^4 - 25     = (x^2+5) (x^2-5)                              =>  factor x^2 - 5

x^4 - 25 =   (x^2+5)(x + sqrt(5)) (x - sqrt(5))       => factor x^2 + 5

x^4 = 25  = (x +5i)(x-5i) (x + sqrt(5)) (x - sqrt(5))  

Hence the solutions are

x = +\- 5i and x = +\- sqrt(5)



Thank you,


MrB

5 0
3 years ago
Super easy problem its just graphing!! will mark brainliest <33
Sonbull [250]

Answer:

y\ =\ \left|\frac{1}{2}x-2.5\right|+3

Step-by-step explanation:

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5 0
3 years ago
Read 2 more answers
You are given the information that P(A) = 0.30 and P(B) = 0.40.
Ad libitum [116K]

Answer:

1.B. No. You need to know the value of P(A and B). 2.C. Yes P(A and B) =0, so P(A or B) = P(A) + P(B).

Step-by-step explanation:

We can solve this question considering the following:

For two mutually exclusive events:

\\ A_{1}\;and\;A_{2}

\\ P(A_{1} or A_{2}) = P(A_{1}) + P(A_{2}) (1)

An extension of the former expression is:

\\ P(A_{1} or A_{2}) = P(A_{1}) + P(A_{2}) - P(A_{1} and A_{2}) (2)

In <em>mutually exclusive events,</em> P(A and B) = 0, that is, the events are <em>independent </em>one of the other, and we know the probability that <em>both events happen</em> <em>at the same time is zero</em> (P(A <em>and</em> B) = 0). There are some other cases in which if event A happens, event B too, so they are not mutually exclusive because P(A <em>and</em> B) is some number different from zero. Notice the difference between <em>OR</em> and <em>AND. The latter implies that both events happen at the same time.</em>

In other words, notice that the formula (2) provides an extension of formula (1) for those events that are not <em>mutually exclusive</em>, that is, there are some cases in which the events share the same probabilities in a way that these probabilities <em>must be subtracted</em> from the total, so those probabilities in common do not "inflate" the actual probability.

For instance, imagine a person going to a gas station and ask for checking both a tire and lube oil of his/her car. The probability for checking a tire is P(A)=0.16, for checking lube oil is P(B)=0.30, and for both P(A and B) = 0.07.

The number 0.07 represents the probability that <em>both events occur at the same time</em>, so the probability that this person ask for checking a tire or the lube oil of his/her car is:

P(A or B) = 0.16 + 0.30 - 0.07 = 0.39.

That is why we cannot simply add some given probabilities <em>without acknowledging if the events are or not mutually exclusive</em>, whereas we can certainly add the probabilities in question when we know that both probabilities are <em>mutually exclusive</em> since P(A and B) = 0.

In conclusion, knowing the events are mutually exclusive <em>does</em> provide <em>extra information</em> and we can proceed to simply add the probabilities of either event; thus, the answers are those in which <em>we need to previously know the value of P(A and B)</em>.  

7 0
2 years ago
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