Step-by-step explanation:
6|8-y|-15
6|8-10|-15
6|-2|-15
6(2)-15
12-15
-3
If your question is how many positions are possible, then the answer is 24.
We find this by thinking of how many people can be in each spot. If there are 4 spots each person can stand (back left, back right, front left, front right), then there are 4 possible choice for the first spot (mom, dad, son, daughter), then 3 for the next spot (since 1 is already in a spot), then 2 options for the next spot, and then 1 option for the last spot. In other words, the answer is 4x3x2x1, or 4 factorial.
Answer:
The center/ mean will almost be equal, and the variability of simulation B will be higher than the variability of simulation A.
Step-by-step explanation:
Solution
Normally, a distribution sample is mostly affected by sample size.
As a rule, sampling error decreases by half by increasing the sample size four times.
In this case, B sample is 2 times higher the A sample size.
Now, the Mean sampling error is affected and is not higher for A.
But it's sample is huge for this, Thus, they are almost equal
Variability of simulation decreases with increase in number of trials. A has less variability.
With increase number of trials, variability of simulation decreases, so A has less variability.
Answer: y=3*2+2
Step-by-step explanation:
Normally You would need to simplify all of them, to see what their values are like.
Already from the start, however, we can see that 9n + 3 + 2 and 9n + 11 isnt the same value. Based on this, we should only need to simplify one of the other, to get either 9n + 5 or 9n + 11.
Lets pick the upper one.
(4n + 3) + 5n + 8 - 6
4n + 3 +5n + 2
9n + 5.
This indicated that 9n+11 is the odd one.
To make sure, we can solve the next one:
(4n + 5n) + (3 + 8 - 6)
9n + 5
Which indicated the same thing.
9n+11 is the "outsider", which means:
9n + 11 is the correct answer for this task.
