Answer: 1.106 s
Step-by-step explanation:
This situation is related to projectile motion and one the equation that models the height of the blueberry pie in time is:
![y=y_{o}+V_{o}sin(\theta) t-\frac{1}{2}gt^{2}](https://tex.z-dn.net/?f=y%3Dy_%7Bo%7D%2BV_%7Bo%7Dsin%28%5Ctheta%29%20t-%5Cfrac%7B1%7D%7B2%7Dgt%5E%7B2%7D)
Where:
is the blueberry pie final height (when it hits the ground)
is the blueberry pie initial height
is the blueberry pie initial velocity
is the angle, assuming the pie was shot horizontally
is the time
is the acceleration due gravity
Rewriting the equation:
![0=y_{o}-\frac{1}{2}gt^{2}](https://tex.z-dn.net/?f=0%3Dy_%7Bo%7D-%5Cfrac%7B1%7D%7B2%7Dgt%5E%7B2%7D)
Isolating
:
![t=\sqrt{\frac{2y_{o}}{g}}](https://tex.z-dn.net/?f=t%3D%5Csqrt%7B%5Cfrac%7B2y_%7Bo%7D%7D%7Bg%7D%7D)
![t=\sqrt{\frac{2(6 m)}{9.8 m/s^{2}}}](https://tex.z-dn.net/?f=t%3D%5Csqrt%7B%5Cfrac%7B2%286%20m%29%7D%7B9.8%20m%2Fs%5E%7B2%7D%7D%7D)
Finally:
![t=1.106 s](https://tex.z-dn.net/?f=t%3D1.106%20s)
(y + 1)^3 would just be dividing the two
If you want it completely simplified, then it’s the following:
(y + 1)(y + 1)(y + 1)
= y^2 + y + y + 1 (y + 1)
= y^2 + 2y + 1 (y + 1)
= y^3 + y^2 + 2y^2 + 2y + y + 1
= y^3 + 3y^2 + 3y + 1
Answer: -33255 + 30![\sqrt{6}](https://tex.z-dn.net/?f=%5Csqrt%7B6%7D)
Step-by-step explanation:
I would assume that you convert 2.5 ounces into punds which would make it 0.15 lbs.
The y-intercept is 50 and it tells how many chocolates he starts off with. The slop is -4 because that is how many chocolates he gives out each week. y=-4x+50