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pychu [463]
3 years ago
11

Read the question below. Or above •-•

Mathematics
2 answers:
serious [3.7K]3 years ago
4 0
The answer is A
Explanation:
V=0.5*b*a*h
yulyashka [42]3 years ago
3 0

Answer:

C

Step-by-step explanation:

Multiply 12*8*34, then divide by 2

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WHOEVER GETS THIS RIGHT IN 3 MINUTES GETS THE BRAINLIEST!! Four times the sum of a number and 15 is at least 120. Let x represen
larisa [96]

Hey there!

Let's call this "number" x. We want four times the sum of this number and 15 to equal at least 120.

Therefore, we want this number times four plus fifteen to be greater than or equal to 120. We have:

4(x+15)\geq 120

Distribute:

4x + 60 \geq 120

Subtract:

4x\geq 60

Divide:

x\geq 15

Your answer is C.

Hope this helps!

7 0
3 years ago
Ned help with this don't anwser if you don't know​
Delvig [45]

Answer:

f(x) = 2x + 2

Step-by-step explanation:

1×2=2+2=4

3×2=6+2=8

and keep going

6 0
3 years ago
Convert 3 over 8 to a decimal and tell whether it terminates or repeats.
Stels [109]
I think the answer is c
8 0
4 years ago
Read 2 more answers
A) Find the area of the shaded region<br> ill give you brainliest​
GenaCL600 [577]

Answer:

2.0

Step-by-step explanation:

Area of Shaded Region = Area of square – Area of circle

Area of square = 3×3 = 9

Area of circle = π×r² = π×1.5² ≈ 7.068

(radius of circle is half of the side length)

9–7.068≈2.0

5 0
3 years ago
You bought your car for $12500 and it is depreciating at 13% per year. How long until it is only worth half of what you paid for
il63 [147K]

Answer:

5 years

Step-by-step explanation:

We are given;

  • Initial value of the car = $12,500
  • Rate of Depreciation = 13% per year
  • New value (after depreciation) = $6,250 (half the initial value)

We are required to determine the time taken for the value of the car to depreciate to half the original value.

  • We need to know the depreciation formula;
  • New value = Initial value ( 1 - r/100)^n

Therefore;

$6,250 = $12,500(1 - r/100)^n

0.5 = (1 - 13/100)^n

0.5 = 0.87^n

Introducing log on both sides;

log 0.5 = n log 0.87

Therefore;

n = log 0.5 ÷ log 0.87

  = 4.977

  = 5 years

Therefore, it takes 5 years for the value of the car to depreciate to half the initial value.

5 0
4 years ago
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