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3 years ago

HELP PLEASE! FOR EACH RELATION, DECIDE WHETHER OR NOT IT IS A FUNCTION.

Mathematics

1 answer:

Mashutka [201]3 years ago

4 0

Answer:

relation 1: function

Relation 2: function

relation 3: not a function

relation 4: not a function

Explanation:

There should be no repeating values in the domain for the relation to qualify for a function.

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Solve the system of equations. (HINT: use the elimination method) 7x+4y=2 9x-4y=30

igor_vitrenko [27]

Answer: 7x + 4 y = 2

9x - 4y= 30

-------------------

16x / = 32

x= 32:16

x=2

Step-by-step explanation: 7x+4y=2

7*2 + 4y=2

14 +4y=2

4y= 2-14

4y= -12

y= -12 : 4

y= - 3

4 0

3 years ago

Please anyone who knows how to do this ... Please help

icang [17]

9. 1/2 & 4/8

10. 1/3 & 4/12

11. 2/4 & 1/2

12. 5/10 & 10/20

13. 2/6 & 4/12

14. 4/6 & 8/12

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3 years ago

A distribution has the five-number summary shown below. What is the

Irina-Kira [14]

Answer:

The interquartile range(IQR) is 31.

Step-by-step explanation:

Given:

A distribution has the five-number summary shown below:

24, 36, 42, 57, 65.

Now, to find the interquartile range (IQR).

So, to get the IQR we need to find the quartile 1 and quartile 3:

As, 42 is the median.

Quartile 1 is the average of first half.

24, 36, 42, 57, 65.

Q1 = $\frac{24+36}{2}$

Q1 = $\frac{60}{2}$

Q1 = $30$

Quartile 3 is the average of last half.

24, 36, 42, 57, 65.

Q3 = $\frac{57+65}{2}$

Q3 = $\frac{122}{2}$

Q3 = $61$

Thus, by putting the formula we get IQR:

IQR = Q3 - Q1.

$IQR=61-30$

$IQR=31.$

Therefore, the interquartile range(IQR) is 31.

4 0

3 years ago

A park ranger hiked 3/4 mi to a lookout, another 5/7 mi to a bird's nest, and finally 5/14 mi to a campsite. How far did the par

svetlana [45]

Answer2/5

Step-by-step explanation:

3 0

3 years ago

PLS HELP ITS URGENT!!

suter [353]

2(pi)r = 9.4in
(pi)r = 4.7in
3.14r = 4.7in
r = 1.497in

Surface Area Of a Sphere = 4(pi)r^2 = [4(3.14)(1.497)^2]in^2 = 28.147in^2 = 28in^2
Volume Of a Sphere = 4/3(pi)r^3 = [4/3(3.14)(1.497)^3]in^3 =14.05in^3 = 14in^3

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2 years ago

HELP PLEASE! FOR EACH RELATION, DECIDE WHETHER OR NOT IT IS A FUNCTION.​

HELP PLEASE! FOR EACH RELATION, DECIDE WHETHER OR NOT IT IS A FUNCTION.