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3 years ago

Which variable is represented by the following symbol? ∑F

Physics

1 answer:

mario62 [17]3 years ago

5 0

Answer:

d.Net force

Explanation:

The net force is the force which is the sum of all the forces acting on an object simultaneously.

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Reika [66]

Answer:

1 point?

Explanation:

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3 years ago

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A sounding rocket can generate a net upward force of 1,700 N of thrust during its 8 second burn. If the rocket has a mass of 200

Jet001 [13]

Answer:

The average acceleration of the rocket, a = 8.5 m/s²

Explanation:

Given that,

The upward force of the rocket, F = 1700 N

The time duration of rocket exerted the force, t = 8 s

The mass of the rocket, m = 200 Kg

The force exerted by the rocket is equal to the product of its mass and acceleration.

Therefore, the formula for force

a = F / m

Substituting the given values in the above equation

a = 1700 N / 200 Kg

= 8.5 m/s²

Hence, the acceleration of the rocket is, a = 8.5 m/s²

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3 years ago

A uniform charge density of 509 nC/m3 is distributed throughout a spherical volume of radius 6.03 cm. Consider a cubical Gaussia

Artemon [7]

Explanation:

(a) It is known that relation between charge and volume is as follows.

$q_{enclosed} = \rho V_{cube}$

= $(509 \times 10^{-9} C/m^{3}) \times (0.04 m)^{3}$

= $509 \times 10^{-9} \times 6.4 \times 10^{-5}$

= $3.26 \times 10^{-11} C$

Now, according to Gauss's law

$\phi = \frac{q_{enclosed}}{\epsilon_{o}}$

= $\frac{3.26 \times 10^{-11} C}{8.85 \times 10^{-12}C^{2}N^{-1}m^{-2}}$

= 3.68 $N m^{2}/C$

Hence, the electric flux through this cubical surface if its edge length is 4.00 cm is 3.68 $N m^{2}/C$ .

(b) Similarly, we will calculate the electric flux when edge length is 16.8 cm as follows.

$q_{enclosed} = \rho V_{cube}$

= $(509 \times 10^{-9} C/m^{3}) \times (0.168 m)^{3}$

= $509 \times 10^{-9} \times 4.74 \times 10^{-3}$

= $2.41 \times 10^{-11} C$

Now, according to Gauss's law

$\phi = \frac{q_{enclosed}}{\epsilon_{o}}$

= $\frac{2.41 \times 10^{-11} C}{8.85 \times 10^{-12}C^{2}N^{-1}m^{-2}}$

= 2.72 $N m^{2}/C$

Therefore, the electric flux through this cubical surface if its edge length is 4.00 cm is 2.72 $N m^{2}/C$ .

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4 years ago

Jupiter is 317 times more massive than the Earth. Its gravitational attraction is _____ Earth's.

NeTakaya

That all depends on your distance from the center of each planet.

On the surface of Jupiter, the acceleration of gravity is 2.53 times
its value on the surface of the Earth.

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3 years ago

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A particle whose speed is 50 m/s moves along the line from A(2,1) to B(9,25). Find its velocity vector in the form of ai +bj.

Kitty [74]

To write it in the form ai + bj, we need to find a and b which are:

a = x component

b = y component

length of x = 9 – 2 = 7

length of y = 25 – 1 = 24

tan θ = 24 / 7

θ = 73.74°

a = (50 m/s) cos 73.74

a = 14 m/s

b = (50 m/s) sin 73.74

b = 48 m/s

Hence,

14i + 48j

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3 years ago