distance to the star Betelgeuse: 640 ly
As we know that
also we know that
So the distance of Betelgeuse = 640 ly
distance to the star VY Canis Majoris: 
distance to the galaxy Large Magellanic Cloud: 49976 pc
now we have
distance to Neptune at the farthest: 4.7 billion km
now the order of distance from least to greatest is as following
1. distance to Neptune at the farthest
2. distance of Betelgeuse
3. distance to the star VY Canis Majoris
4. distance to the galaxy Large Magellanic Cloud
The answer is two (4 -3)
Zero is not a SF
We are given an object that is speeding up on a level ground.
Let's remember that the gravitational energy depends on the change in height, therefore, if the object is not changing its height it means that the gravitational energy remains constant.
The kinetic energy depends on the velocity. If the velocity is increasing this means that the kinetic energy is also increasing.
Now, every change in velocity requires acceleration and acceleration requires a force. The force and the distance that the object moves are equivalent to the work that is transferred to the object and therefore, the change in kinetic energy. This means that the total energy of the system increases as work is transferred to the mass.
We have that the total energy of the system increases in the form of kinetic energy and that the gravitational potential energy remains constant. Therefore, the diagrams should look like pie charts that grow but the area of the segment of the potential energy stays the same. It should look similar to the following.
What uhhhhhhhhhhhhhhhhhhhhh
