All categories

4 years ago

Which method is used to assign weights to various features of a system?

Physics

1 answer:

UNO [17]4 years ago

8 0

Portfolio analysis.

Hope this helped, have a great day! :D

You might be interested in

Which of these are types of meteorites? Select all that apply.

love history [14]

The types of meteorites are iron, stone and iron-stony meteorites. The stony-iron meteorites account for less than 2% of all known meteorites. They comprised of roughly equal amounts of nickel-iron and stone and are divided into two groups: pallasites and mesosiderites. The answers are only B and C

8 0

3 years ago

Which of the following (with specific heat capacity provided) would show the smallest temperature change upon gaining 200.0 J of

sergij07 [2.7K]

Answer:

A) 50.0 g Al

Explanation:

We can calculate the temperature change of each substance by using the equation:

$\Delta T=\frac{Q}{mC_s}$

where

Q = 200.0 J is the heat provided to the substance

m is the mass of the substance

$C_s$ is the specific heat of the substance

Let's apply the formula for each substance:

A) m = 50.0 g, Cs = 0.903 J/g°C

$\Delta T=\frac{200}{(50)(0.903)}=4.4^{\circ}C$

B) m = 50.0 g, Cs = 0.385 J/g°C

$\Delta T=\frac{200}{(50)(0.385)}=10.4^{\circ}C$

C) m = 25.0 g, Cs = 0.79 J/g°C

$\Delta T=\frac{200}{(25)(0.79)}=10.1^{\circ}C$

D) m = 25.0 g, Cs = 0.128 J/g°C

$\Delta T=\frac{200}{(25)(0.128)}=62.5^{\circ}C$

E) m = 25.0 g, Cs = 0.235 J/g°C

$\Delta T=\frac{200}{(25)(0.235)}=34.0^{\circ}C$

As we can see, substance A) (Aluminium) is the one that undergoes the smallest temperature change.

7 0

3 years ago

A ball has m=10 kg and v=10 m/s. It has the same momentum as which of the following?

crimeas [40]

Answer:

Choice d. All three balls listed in choice a, b, and c have a momentum of $100\; \rm kg \cdot m \cdot s^{-1}$ each, same as that of the $10\; \rm kg$ ball moving at $10\; \rm m \cdot s^{-1}$ . Assumption: all four balls are moving in the same direction.

Explanation:

The momentum $p$ of an object is equal to the product of its mass $m$ and its velocity $v$ .

Momentum of a $10\; \rm kg$ ball moving at $10\; \rm m \cdot s^{-1}$ :

$p = m \cdot v = 10\; \rm kg \times 10\; \rm m \cdot s^{-1} = 100\; \rm kg \cdot m \cdot s^{-1}$ .

Similarly:

Momentum of the ball in choice a: $100 \; \rm kg \times 1\; \rm m \cdot s^{-1} = 100\; \rm kg \cdot m\cdot s^{-1}$ .
Momentum of the ball in choice b: $5 \; \rm kg \times 20\; \rm m \cdot s^{-1} = 100\; \rm kg \cdot m\cdot s^{-1}$ .
Momentum of the ball in choice c: $2 \; \rm kg \times 50\; \rm m \cdot s^{-1} = 100\; \rm kg \cdot m\cdot s^{-1}$ .