Answer:
Explanation:
Distance of 2 nd order fringe x₁ = 2 λ D/d [ λ is wave length , D is distance of screen , d is slit distance.
x₁ = 2 x 660 x10⁻⁹x 2.55/.65 x 10⁻³.= 5.17846 x 10⁻³ m.
Distance of fringe for 2nd radiation = 5.178 x 10⁻³ -1.17 x 10⁻³ = 4.008 x10⁻³
4.008 x 10⁻³ = 2 x λ x 2.55/.65 x 10⁻³
λ = 511 nm approx.
.
I don't think an object can exert a force on itself.
Try it: Get up on a skateboard, and see if you can do anything to yourself that makes you start moving ... without touching anything else.
It'll be easy to tell if you succeed. If you actually do exert an unbalanced force on yourself, then you'll begin to accelerate.
Green would be best
hope it help
Answer:
The minimum speed is 14.53 m/s.
Explanation:
Given that,
r = 11 m
Friction coefficient = 0.51
Suppose we need to find the minimum speed, that the cylinder must make a person move at to ensure they will stick to the wall
When frictional force becomes equal to or greater than the weight of person
Then, he sticks to the wall
We need to calculate the minimum speed
Using formula for speed
Where, 
Put the value into the formula
Hence, The minimum speed is 14.53 m/s.
It doesn't on account of radio waves are longer than optical waves. Radio waves are a sort of electromagnetic radiation with wavelengths in the electromagnetic range longer than infrared light. These long waves are in the radio locale of the electromagnetic range.
