Answer:
See explanation
Step-by-step explanation:
Car A: Started at 0 and ended at 300, thus, car A travels 300 miles.
It travels 6 hours, so car A speed is
mph.
Car B: Started at 100 and ended at 300, thus, car B travels 300-100=200 miles.
It travels 5 hours, so car B speed is
mph.
Since 50>40, car A traveled faster than car B.
The graph for the car A is steeper than the graph for the car B.
Answer:
<em>The age at which both companies charge the same premium is 44 years</em>
Step-by-step explanation:
<u>Graph Solution to System of Equations</u>
One approach to solving systems of equations of two variables is the graph method.
Both equations are plotted in the same grid and we find the intersection point(s) of both graphs. Those are the feasible solutions.
The annual premium p as a function of the client's age a for two companies are given as:
Company A: p= 2a+24
Company B: p= 2.25a+13
The graphs of both functions are shown in the image below.
The red line indicates the formula for Company A and the blue line indicates the formula for Company B.
It can be seen that both lines intersect in the point with approximate coordinates of (44,112).
The age at which both companies charge the same premium is 44 years
The area of the trapezoid is 37.5 square inches.
By definition we have the following equation:
t = d / v
Where,
t: time
d: distance
v: speed
For this case we have:
d / 30 + d / 4 = 17
Rewriting we have:
2d + 15d = 17 (60)
17d = 17 (60)
d = 60 mi
Then, the walking time is
t = d / v
t = 60/4
t = 15 hours
Answer:
She walked
t = 15 hours
I'm pretty sure there were 48 girls at the beach clean up. 43 ÷ 7 = 6.14 (6 cause there's not gonna be floating males with missing body parts). So we multiply 6 x 8 and we get 48.