The answer is -0.6 using long division.
<span><span> 5n2+10n+20</span> </span>Final result :<span> 5 • (n2 + 2n + 4)
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Reformatting the input :
Changes made to your input should not affect the solution:
(1): "n2" was replaced by "n^2".
Step by step solution :Skip Ad
<span>Step 1 :</span><span>Equation at the end of step 1 :</span><span> (5n2 + 10n) + 20
</span><span>Step 2 :</span><span>Step 3 :</span>Pulling out like terms :
<span> 3.1 </span> Pull out like factors :
<span> 5n2 + 10n + 20</span> = <span> 5 • (n2 + 2n + 4)</span>
Trying to factor by splitting the middle term
<span> 3.2 </span> Factoring <span> n2 + 2n + 4</span>
The first term is, <span> <span>n2</span> </span> its coefficient is <span> 1 </span>.
The middle term is, <span> +2n </span> its coefficient is <span> 2 </span>.
The last term, "the constant", is <span> +4 </span>
Step-1 : Multiply the coefficient of the first term by the constant <span> <span> 1</span> • 4 = 4</span>
Step-2 : Find two factors of 4 whose sum equals the coefficient of the middle term, which is <span> 2 </span>.
<span><span> -4 + -1 = -5</span><span> -2 + -2 = -4</span><span> -1 + -4 = -5</span><span> 1 + 4 = 5</span><span> 2 + 2 = 4</span><span> 4 + 1 = 5</span></span>
1 gallon=3.78541 liters
So 1 gallon is bigger than 2 liters
Answer:
-1,512,390
Step-by-step explanation:
Given
a1 = 15
Let us generate the first three terms of the sequence
For 
Hence the first three terms ae 15, 8, 1...
This sequence forms an arithmetic progression with;
first term a = 15
common difference d = 8 - 15 = - -8 = -7
n is the number of terms = 660 (since we are looking for the sum of the first 660 terms)
Using the formula;
![S_n = \frac{n}{2}[2a + (n-1)d]\\](https://tex.z-dn.net/?f=S_n%20%3D%20%5Cfrac%7Bn%7D%7B2%7D%5B2a%20%2B%20%28n-1%29d%5D%5C%5C)
Substitute the given values;
![S_{660} = \frac{660}{2}[2(15) + (660-1)(-7)]\\S_{660} = 330[30 + (659)(-7)]\\S_{660} = 330[30 -4613]\\S_{660} = 330[-4583]\\S_{660} = -1,512,390](https://tex.z-dn.net/?f=S_%7B660%7D%20%3D%20%5Cfrac%7B660%7D%7B2%7D%5B2%2815%29%20%2B%20%28660-1%29%28-7%29%5D%5C%5CS_%7B660%7D%20%3D%20330%5B30%20%2B%20%28659%29%28-7%29%5D%5C%5CS_%7B660%7D%20%3D%20330%5B30%20-4613%5D%5C%5CS_%7B660%7D%20%3D%20330%5B-4583%5D%5C%5CS_%7B660%7D%20%3D%20-1%2C512%2C390)
Hence the sum of the first 660 terms of the sequence is -1,512,390
