Minimum required sample size for a desired margin of error and confidence level when it is a proportion problem: n = (z2÷margin of error2)*p-hat*q-hat
The maximum value of p-hat*q-hat occurs where p-hat = .5 (found by taking the derivative of (p-hat)*(1-p-hat) and setting it equal to 0 to find the maximum. n = ( 2.5762( for 99% confidence interval)÷.0482 )*.5*.5 = 720.028 or 721
How many miles did he ride each time?? Just add them up
-12 = 6 + 2/3y
Subtract 6 from both sides
-18 = 2/3y
Multiply both sides by 3
-54 = 2y
Divide both sides by 2
-27 = y
It depends what your teacher wants it rounded to. It could be 300,000 if its rounded to the hundred thousands. If it is to the nearest hundred, it would be 384,300.
Answer:
a letter
Step-by-step explanation:
