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sergij07 [2.7K]
3 years ago
13

Help please-8+(-5)+9+11= ​

Mathematics
2 answers:
Paul [167]3 years ago
4 0
-8 - 5 + 9 + 11

-13 + 9 + 11

-4 + 11
= 7
DerKrebs [107]3 years ago
3 0

Answer:

=7

Step-by-step explanation:

= -8+(-5)+9+11

= -8-5+20

= -13+20

= 7

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The daily high temperatures in a vacation resort city are approximately Normal, with a mean temperature of 75 degrees Fahrenheit
zzz [600]

Answer:

i think is the last one

Step-by-step explanation:

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3 years ago
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Geometry B Unit 6: Surface Area and Volume, Lesson 10: Surface Area and Volume Unit Test?
Blababa [14]

Answer:

B

Step-by-step explanation:

Euler's formula for polyhedra states that

F + V - E = 2

where F is faces, V is vertices and E is edges

Substitute the values given and solve for F, that is

F + 13 - 26 = 2

F - 13 = 2 ( add 13 to both sides )

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A coin is tossed twice. What is the probability of getting a tail in the first toss and a tail in the second toss?
skelet666 [1.2K]

Answer:

<h2>1/4 Chances</h2><h2>25% Chances</h2><h2>0.25 Chances (out of 1)</h2>

Step-by-step explanation:

Two methods to answer the question.

Here are presented to show the advantage in using the product rule given above.

<h2>Method 1:Using the sample space</h2>

The sample space S of the experiment of tossing a coin twice is given by the tree diagram shown below

The first toss gives two possible outcomes: T or H ( in blue)

The second toss gives two possible outcomes: T or H (in red)

From the three diagrams, we can deduce the sample space S set as follows

          S={(H,H),(H,T),(T,H),(T,T)}

with n(S)=4 where n(S) is the number of elements in the set S

tree diagram in tossing a coin twice

The event E : " tossing a coin twice and getting two tails " as a set is given by

          E={(T,T)}

with n(E)=1 where n(E) is the number of elements in the set E

Use the classical probability formula to find P(E) as:

          P(E)=n(E)n(S)=14

<h2>Method 2: Use the product rule of two independent event</h2>

Event E " tossing a coin twice and getting a tail in each toss " may be considered as two events

Event A " toss a coin once and get a tail " and event B "toss the coin a second time and get a tail "

with the probabilities of each event A and B given by

          P(A)=12 and P(B)=12

Event E occurring may now be considered as events A and B occurring. Events A and B are independent and therefore the product rule may be used as follows

        P(E)=P(A and B)=P(A∩B)=P(A)⋅P(B)=12⋅12=14

NOTE If you toss a coin a large number of times, the sample space will have a large number of elements and therefore method 2 is much more practical to use than method 1 where you have a large number of outcomes.

We now present more examples and questions on how the product rule of independent events is used to solve probability questions.

8 0
2 years ago
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Plz Help ASAP!!!!!
xz_007 [3.2K]

Answer:

The hypotenuse is square root of 65

Step-by-step explanation:

a^2 + b^2 = c^2

legs of the right triangle are a and b. Just substitute 4 for a and 7 for b and solve.

4^2+7^2=16+49=65

c^2=65

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c=the square root of 65

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2 years ago
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Someone help me with question 2???
postnew [5]
Surface area is the area of all the surfaces we can touch
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1/2*5*3+1/2*4*3+6*4+6*5 which is
67.5

b) 2*(1/2*10*6)+12*6+12*10 which is
252
5 0
3 years ago
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