Ask question

Ask question

All categories

3 years ago

7

1.out of 100 students it was found that 65 liked volleyball,55 liked football and 35 liked both the games.find how many students

didn't like both games by using venn diagram.

1 answer:

Elza [17]3 years ago

3 0

S = Universe of discourse, A = students that likes volleyball, while B likes football

You might be interested in

You have two exponential functions. One has the formula h(x) = 2 x + 3. The other function, g(x), has the graph shown below.

Alex17521 [72]

To answer, we substitute each of the numbers in parentheses to x of h(x) and get the value of g(x).

A. h(2) = 2(2) + 3 = 7 ; g(2) < 4 (neither is equal to 7)

B. h(7) = 2(7) + 3 = 17; g(7) is not shown in the graph (not true)

C. h(2) = 7 ; g(2) < 4 Thus, g(2) < h(2) (choice is not true)

D. From C, g(2) < h(2) (TRUE)

Thus, the answer to this item is letter D.

5 0

3 years ago

Read 2 more answers

Sam used 6 loaves of elf bread on a 8 day hiking trip. He wants to know how many loaves of elf bread he should pack for a 12 day

KonstantinChe [14]

If he eats 6 loaves in 8 days, that means he ate 0.75 of a loaf each day. (6 divided by 8 = 0.75)
In a 12 day trip,
# divided by 12 = 0.75;
so to undo division, you multiply.
12 x 0.75 = #
# = 9. So 9 loaves for 12 days.

5 0

3 years ago

Is 8 yd greater than 288 in.

jonny [76]

3 feet is equal to 1 yard and 3 feet is 36 inches. 288 inches divided by 36 is 8 so 8 yards is equal to 288 inches.

8 0

3 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=%20%20%5Csf%20%5Chuge%7B%20question%20%5Chookleftarrow%7D" id="TexFormula1" title=" \sf \huge

BabaBlast [244]

$\underline{\bf{Given \:equation:-}}$

$\\ \sf{:}\dashrightarrow ax^2+by+c=0$

$\sf Let\:roots\;of\:the\: equation\:be\:\alpha\:and\beta.$

$\sf We\:know,$

$\boxed{\sf sum\:of\:roots=\alpha+\beta=\dfrac{-b}{a}}$

$\boxed{\sf Product\:of\:roots=\alpha\beta=\dfrac{c}{a}}$

$\underline{\large{\bf Identities\:used:-}}$

$\boxed{\sf (a+b)^2=a^2+2ab+b^2}$

$\boxed{\sf (√a)^2=a}$

$\boxed{\sf \sqrt{a}\sqrt{b}=\sqrt{ab}}$

$\boxed{\sf \sqrt{\sqrt{a}}=a}$

$\underline{\bf Final\: Solution:-}$

$\\ \sf{:}\dashrightarrow \sqrt{\alpha}+\sqrt{\beta}$

$\bull\sf Apply\: Squares$

$\\ \sf{:}\dashrightarrow (\sqrt{\alpha}+\sqrt{\beta})^2= (\sqrt{\alpha})^2+2\sqrt{\alpha}\sqrt{\beta}+(\sqrt{\beta})^2$

$\\ \sf{:}\dashrightarrow (\sqrt{\alpha}+\sqrt{\beta})^2 \alpha+\beta+2\sqrt{\alpha\beta}$

$\bull\sf Put\:values$

$\\ \sf{:}\dashrightarrow (\sqrt{\alpha}+\sqrt{\beta})^2=\dfrac{-b}{a}+2\sqrt{\dfrac{c}{a}}$

$\\ \sf{:}\dashrightarrow \sqrt{\alpha}+\sqrt{\beta}=\sqrt{\dfrac{-b}{a}+2\sqrt{\dfrac{c}{a}}}$

$\bull\sf Simplify$

$\\ \sf{:}\dashrightarrow \underline{\boxed{\bf {\sqrt{\boldsymbol{\alpha}}+\sqrt{\boldsymbol{\beta}}=\sqrt{\dfrac{-b}{a}}+\sqrt{2}\dfrac{c}{a}}}}$

$\underline{\bf More\: simplification:-}$

$\\ \sf{:}\dashrightarrow \sqrt{\alpha}+\sqrt{\beta}=\dfrac{\sqrt{-b}}{\sqrt{a}}+\dfrac{c\sqrt{2}}{a}$

$\\ \sf{:}\dashrightarrow \sqrt{\alpha}+\sqrt{\beta}=\dfrac{\sqrt{a}\sqrt{-b}+c\sqrt{2}}{a}$

$\underline{\Large{\bf Simplified\: Answer:-}}$

$\\ \sf{:}\dashrightarrow\underline{\boxed{\bf{ \sqrt{\boldsymbol{\alpha}}+\sqrt{\boldsymbol{\beta}}=\dfrac{\sqrt{-ab}+c\sqrt{2}}{a}}}}$

5 0

2 years ago

Read 2 more answers

What is the median of the following list of numbers?

Novay_Z [31]

Answer:

The answer is 11.

Step-by-step explanation:

First, you put all of the numbers in order, from 7 - 19.

You find the median. You should get 11 and 11.

You add the numbers up to get 22 and divide by 2.

5 0

3 years ago