Start at 92. Create a pattern that adds 13 to each stop after 5 numbers

What is the equation in point slope form of the line that passes the points (2,-3) and(-5,8)

Grace [21]

Answer:

y+3=-11/7(x-2)

Step-by-step explanation:

y-y1=m(x-x1)

m=(y2-y1)/(x2-x1)

m=(8-(-3))/(-5-2)

m=(8+3)/(-7)

m=11/-7

m=-11/7

y-(-3)=-11/7(x-2)

y+3=-11/7(x-2)

4 0

2 years ago

What is the inverse of the function f(x) = 2x - 10?

Oxana [17]

Answer:

h(x) = 1/2x + 5

Step-by-step explanation:

Switch the positions of the x and y (f(x)) and solve for y (f(x)).

f(x) = 2x - 10

x = 2y - 10

x + 10 = 2y

(x + 10)/2 = y

1/2x + 5 = y

3 0

2 years ago

Find the distance from the point (4,2) to the point (0,1).

vagabundo [1.1K]

Answer:

4.123 units

Step-by-step explanation:

Data provided:

Coordinates of point 1 as ( 4 , 2)

and,

Coordinates of point 2 as ( 0 , 1 )

Now,

The distance between the two point whose coordinates are given is calculated using the formula as:

distance = $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

on substituting the values, we get

distance = $\sqrt{(0-4)^2+(1-2)^2}$

or

distance = $\sqrt{(-4)^2+(-1)^2}$

or

distance = $\sqrt{16+1}$

or

Distance = √17 = 4.123 units

6 0

3 years ago

Algebra There were 4 times the number of students in fourth grade at the basketball game.How many students attended the basketba

denis-greek [22]

Answer:

200 students attended the basketball game

Step-by-step explanation:

The complete question in the attached figure

Let

x ------> the number of students in fourth grade

s -----> the number of students at the basketball game

we know that

The number of students at the basketball game is four times the number of students in fourth grade

so

The linear expression is

$s=4x$ -----> equation A

$x=50\ students\ in\ fourth\ grade$ -----> equation B

substitute equation B in equation A and solve for y

$s=4(50)$

$s=200\ students\ at\ the\ basketball\ game$

therefore

200 students attended the basketball game

8 0

2 years ago

The area of a triangle is 15x^4+3x^3+4x^2-x-3 square meters. The length of the base of the triangle is 6x^2-2 meters. What is th

MArishka [77]

Answer:

The height of the triangle is: $H = (5x^2 + x +3)$

Step-by-step explanation:

Here, the area the triangle is given as: $15x^4 + 3x^3 + 4x^2 - x - 3$

Also, base of the triangle = $(6x^2 -2)$

Let us assume the height of the triangle = H units

Now, AREA of TRIANGLE = $\frac{1}{2} \times B \times H$

$\implies (15x^4+3x^3+4x^2-x-3 ) = \frac{1}{2} \times ( 6x^2-2) \times H\\\implies H =\frac{ (15x^4+3x^3+4x^2-x-3 )}{(3x^2-1)}$

Solving by LONG DIVISION, we get:

$H = (5x^2 + x +3)$

Hence, the height of the triangle is: $H = (5x^2 + x +3)$

6 0

3 years ago