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JulijaS [17]
3 years ago
6

Start at 92. Create a pattern that adds 13 to each stop after 5 numbers

Mathematics
1 answer:
Anit [1.1K]3 years ago
3 0
92, 105, 118, 131, 144, 157
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Answer please ill give brainlist and ten points
Dmitry_Shevchenko [17]

Answer:

The answer is 32.

Step-by-step explanation:

7 * A =

7 * 4 = 28

b^2 =

6^2 = 36

28 + 36 ÷ 9 = 32

So, the answer is 32.

Hope this helps! :)

3 0
3 years ago
Liam explains that drawing a yellow card is equivalent to drawing a blue card followed by a red card how many spaces forward or
Ivenika [448]

Complete question :

designs a board game in which a card is drawn on each turn. • A blue card means move forward 4 squares. • A red card means move back 6 squares. Liam suggests adding some other cards to Sia's game Part A Liam explains that drawing a yellow card is equivalent to drawing a blue card followed by a red card. How many spaces forward or backward does a player move after drawing a yellow card? Justify your answer.

Answer:

2 squares backward

Step-by-step explanation:

Given the rule :

Blue card = 4 squares forward

Red card = 6 squares backward

Yellow card = drawing a blue followed by a red

Spaces moved after drawing a yellow card:

Yellow equals :

Blue = + 4 squares ; then

Red = - 6 squares

Net total movement :

Blue + red

+4 + (-6)

4 - 6

- 2

2 squares backward

7 0
3 years ago
Please answer please please
elena-14-01-66 [18.8K]

Answer:

6=2r please mark brainliest

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Properties of rectangle <br>and your free fire id<br>​
Tamiku [17]

Answer:

i am not play free fire

muje school dhyan nahi ate eseleye

8 0
3 years ago
A is a 3 times 3 matrix with three pivot positions.
saw5 [17]

Answer:

The following are the answer:

In option a  "No".

In option b  "Yes".

Step-by-step explanation:

In choice a:

Ax = 0 has no nontrivial solution. A would be the three-pivot matrix, it may assume, that the function has no free variable, and only if the function has had at least one free factor are their nontrivial formulas for the equations of the form Ax=0.  

It implies that since A is a 3x3 matrix, has no free variables so that it has no non-trivial choices, and Ax = 0.

In choice b:

we assume that every potential has at least one solution that is Ax=b . If A does have a three-pivot matrix, It will be a pivot element for each row and column, and for each possible b∈ R³, Ax = b has at least one solution.

7 0
3 years ago
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