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Naya [18.7K]
4 years ago
9

Give examples from our daily lives on each of the 4 factors that affect the rate of the reaction. (Concentration, Surface Area,

Temperature, Catalysts)
Chemistry
1 answer:
LenKa [72]4 years ago
6 0
Chemists use reactions to generate a desired product. For the most part, a reaction is only useful if it occurs at a reasonable rate. For example, a reaction that took 8,000 years to complete would not be a desirable way to produce brake fluid. However, a reaction that proceeded so quickly that it caused an explosion would also not be useful (unless the explosion was the desired result). For these reasons, chemists wish to be able to control reaction rates. In order to gain this control, we must first know what factors affect the rate of a reaction. We will discuss some of these factors in this section.
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When Na forms an ion it loses its outer electron to become Na+. Write the electron configuration for Na and Na+. What element do
Otrada [13]

Answer:

Na: 1s2 2s2 2p6 3s1

Na+: 1s2 2s2 2p6

Na+ electronic configuration resemble that of Neon( 1s2 2s2 2p6)

In general, the electronic configuration of alkali metals ions resemble that of the group zero (noble gas)

3 0
4 years ago
Give the formulas of the compounds in each set (a) lead(l|) oxide and lead(lV) oxide; (b) lithium nitride, lithium nitrite, and
Ivanshal [37]

<u>Answer:</u>

<u>For a:</u> The formula of lead (II) oxide and lead (IV) oxide is PbO\text{ and }PbO_2 respectively.

<u>For b:</u> The formula of lithium nitride, lithium nitrite and lithium nitrate is Li_3N,LiNO_2\text{ and }LiNO_3 respectively.

<u>For c:</u> The formula of Strontium hydride and strontium hydroxide is SrH_2\text{ and }Sr(OH)_2 respectively.

<u>For d:</u> The formula of magnesium oxide and manganese (II) oxide is MgO\text{ and }MnO respectively.

<u>Explanation:</u>

All the given compounds are ionic compounds. This means that between the atoms complete sharing of electrons takes place.

  • <u>For a:</u>

Lead is the 82th element of periodic table having electronic configuration of [Xe]4f^{14}5d^{10}6s^26p^2.

To form Pb^{2+} ion, this element will loose 2 electrons and to form Pb^{4+} ion, this element will loose 4 electrons.

Oxygen is the 8th element of periodic table having electronic configuration of [He]2s^22p^4.

To form O^{2-} ion, this element will gain 2 electrons.

By criss-cross method, the oxidation state of the ions gets exchanged and they form the subscripts of the other ions. This results in the formation of a neutral compound.

So, the chemical formula for lead (II) oxide is PbO and for lead (IV) oxide is PbO_2

Thus, the formula of lead (II) oxide and lead (IV) oxide is PbO\text{ and }PbO_2 respectively.

  • <u>For b:</u>

Lithium is the 3rd element of periodic table having electronic configuration of [He]2s^1.

To form Li^{+} ion, this element will loose 1 electron.

Nitrogen is the 7th element of periodic table having electronic configuration of [He]2s^22p^3.

To form N^{3-} ion, this element will gain 3 electrons.

Nitrite ion is a polyatomic ion having chemical formula of NO_2^{-}

Nitrate ion is a polyatomic ion having chemical formula of NO_3^{-}

By criss-cross method, the oxidation state of the ions gets exchanged and they form the subscripts of the other ions. This results in the formation of a neutral compound.

So, the chemical formula for lithium nitride is Li_3N, for lithium nitrite is LiNO_2 and for lithium nitrate is LiNO_3

Thus, the formula of lithium nitride, lithium nitrite and lithium nitrate is Li_3N,LiNO_2\text{ and }LiNO_3 respectively.

  • <u>For c:</u>

Strontium is the 38th element of periodic table having electronic configuration of [Kr]5s^2.

To form Sr^{2+} ion, this element will loose 2 electrons.

Hydrogen is the 1st element of periodic table having electronic configuration of 1s^1.

To form H^{-} ion, this element will gain 1 electron and is named as hydride ion.

Hydroxide ion is a polyatomic ion having chemical formula of OH^{-}

By criss-cross method, the oxidation state of the ions gets exchanged and they form the subscripts of the other ions. This results in the formation of a neutral compound.

So, the chemical formula for strontium hydride is SrH_2 and for strontium hydroxide is Sr(OH)_2

Thus, the formula of Strontium hydride and strontium hydroxide is SrH_2\text{ and }Sr(OH)_2 respectively.

  • <u>For d:</u>

Magnesium is the 12th element of periodic table having electronic configuration of [Ne]3s^2.

To form Mg^{2+} ion, this element will loose 2 electrons.

Manganese is the 25th element of the periodic table having electronic configuration of [Ar]3d^54s^2

To form Mn^{2+} ion, this element will loose 2 electrons.

Oxygen is the 8th element of periodic table having electronic configuration of [He]2s^22p^4.

To form O^{2-} ion, this element will gain 2 electrons.

By criss-cross method, the oxidation state of the ions gets exchanged and they form the subscripts of the other ions. This results in the formation of a neutral compound.

So, the chemical formula for magnesium oxide is MgO and for manganese (II) oxide is MnO.

Thus, the formula of magnesium oxide and manganese (II) oxide is MgO\text{ and }MnO respectively.

7 0
3 years ago
THE FIRST ONE TO ANSWER GETS BRAINLIEST!!!!!!!!!!!!!!!!! HURRY UP!!!!!!!!!!HELP!!!!
Serjik [45]

The answer is A. an ore.

8 0
3 years ago
Read 2 more answers
Methylcyclopentene reacting with reacting with sulfuric acid and water
dlinn [17]

Answer:

The product is 1-methylcyclopentanol  

Explanation:

The acid-catalyzed hydration of alkenes involves the addition of a water molecule to a C=C double bond.

H₂O + C=C ⟶ H-C-C-OH

An H atom adds to one of the C atoms, and an OH group adds to the other

This reaction follows Markovnikov’s rule — the H adds to the C atom that has more hydrogen atoms, and the OH adds to the more substituted carbon.

The steps of the mechanism are:

  1. The aqueous sulfuric acid generates hydronium ions
  2. The nucleophilic π electrons attack an H atom  on the hydronium ion, forming a carbocation on the more substituted C atom.
  3. The lone pair electrons on a water molecule attack the carbocation , forming an oxonium ion.
  4. Another water molecule removes the extra proton.

The product is the alcohol with the OH group on the more substituted carbon — 1-methylcyclopentanol.

7 0
4 years ago
Fill in the blanks for the drawing of a voltaic cell that’s made with copper/copper (II) nitrate (E° = 0.34 V) and zinc/zinc (II
Elodia [21]

Answer:

Hi Im an online tutor and i can assist you with all your assignments. We have experts in all fields. check out our website https://toplivewriters.com/

Explanation:

4 0
3 years ago
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