This is done by reducing each number by a common factor for each formula.
C3H6O6- all can be divided by 3 -> CH3O3 (you don't have to put a 1 for C, only if your teacher requests it. It is generally understood if not written)
H2O2- all can be divided by 2 -> H1O1 (had to put the 1's bc of the unintended language)
C8H8S2- all can be divided by 2 -> C4H4S
P5O15- all can be divided by 5- PO3
*****it is important to note that <em>all </em>numbers in the molecular formula are divided by the same thing to reduce them. decimals are <em>never </em>used in empirical formulas, only whole numbers.*****
<u>Answer:</u> The correct answer is 1.
<u>Explanation:</u>
When alkanes are reacted with chlorine gas at high temperatures or in the presence of light, it leads to the formation of chloro alkanes.
The process is known as chlorination.
Let us take the simplest alkane which is methane having chemical formula 
The chemical equation for the chlorination of methane follows:
![CH_4+Cl_2\xrightarrow[]{h\nu}CH_3Cl+HCl](https://tex.z-dn.net/?f=CH_4%2BCl_2%5Cxrightarrow%5B%5D%7Bh%5Cnu%7DCH_3Cl%2BHCl)
The product formed is chloromethane.
Hence, the correct answer is 1.
Answer:
The answer to your question is:
Re (III) has 5 electrons
Sc(III) = has 1 electron
Ru(IV) = has 6 electrons
Hg(II) = has 10 electrons
Explanation:
75 Re(III) = 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d¹⁰ 5p⁶ 6s² 4f¹⁴ 5d⁵
21 Sc(III) = 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹
44 Ru(IV) = 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d⁶
80 Hg(II) = 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d¹⁰ 5p⁶ 6s² 4f¹⁴ 5d¹⁰
Answer:
C
Explanation:
it has to have hydroniums
