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3 years ago

Solve the equation -3 = -13 - 5x for x

Mathematics

2 answers:

ipn [44]3 years ago

8 0

Hope this will help u...

Law Incorporation [45]3 years ago

6 0

Answer:

x = -2

Step-by-step explanation:

-3 = -13 - 5x

-3 + 13 = -5x

10 = -5x

10 ÷ (-5) = x

-2 = x

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5 0

3 years ago

Read 2 more answers

Find the sum \[\sum_{k = 1}^{2004} \frac{1}{1 + \tan^2 (\frac{k \pi}{2 \cdot 2005})}.\]

vampirchik [111]

Answer:1002

Step-by-step explanation:

$\Rightarrow \sum_{k=1}^{2004}\left ( \frac{1}{1+\tan ^2\left ( \frac{k\pi }{2\cdot 2005}\right )}\right )$

and $1+\tan ^2\theta =\sec^2\theta$

and $\cos \theta =\frac{1}{\sec \theta }$

$\Rightarrow \sum_{k=1}^{2004}\left ( \cos^2\frac{k\pi }{2\cdot 2005}\right )$

as $\cos ^2\theta =\cos ^2(\pi -\theta )$

Applying this we get

$\Rightarrow \sum_{1}^{1002}\left [ \cos^2\left ( \frac{k\pi }{2\cdot 2005}\right )+\cos^2\left ( \frac{(2005-k)\pi }{2\cdot 2005}\right )\right ]$

every $\theta$ there exist $\pi -\theta$

such that $\sin^2\theta +\cos^2\theta =1$

therefore

$\Rightarrow \sum_{1}^{1002}\left [ \cos^2\left ( \frac{k\pi }{2\cdot 2005}\right )+\cos^2\left ( \frac{(2005-k)\pi }{2\cdot 2005}\right )\right ]=1002$

6 0

3 years ago

MATH HELP PLEASE?

Illusion [34]

Answer:

The IQR of the given data is 6. Therefore the correct option is B.

Step-by-step explanation:

The formula for interquartile range is

$IQR=Q_3-Q_1$

In a box plot the left end of line represents the minimum value of data set and right end of line represents the maximum value of data set.

The left end of box represents the first quartile and right end of the box represents the third quartile. The line between the box represent the median.

From the given box plot it is clear that,

$Minimum=7$