1. a)CK²=CH²+HK², CH - radius
CH²=CK²-HK²=50²-30²=2500-900=1600 ft²
CH=40 ft -- radius
b) cos(KCH)= CH/CK=40/50=4/5
KCH=arccos(4/5)≈36.87°
2)C=2πr≈2*3.14*40=251.2 ft
C=2*40π=80π ft --- exact
3) A =πr²=40²π=1600π ----exact
A≈1600*3.14=5024 ft
Answer:
To provide a situation of 1 and O, here is a situation
Step-by-step explanation:
The acceleration would be 1.
If the acceleration is 10 m/s, the object will gain more speed.
On the other hand, if the acceleration is -10m/s, then the object will lose speed.
In the case of 1, the object gained more speed, in the case of 0, the object will lose speed.
Answer:
4.2 units
most likely answer choice B
Step-by-step explanation:
(1, 2) and (4, 5)
To find the distance between two points, we use the distance formula:

Let's plug in what we know.

Evaluate the parentheses.

Evaluate the exponents.

Add.

Evaluate the radical.
d = 4.24
Round to the nearest tenth.
d = 4.2 units
*note: The answer choice is 4.6. I'm not sure if that is a typo on someone's end, but the distance between these two points is exactly 4.24264068712 units.
Hope this helps!
The area of the shape is 230 cm.