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2 years ago

HELP ME ASPPP! GIVE OUT POINT

Mathematics

2 answers:

Llana [10]2 years ago

7 0

U said free points !!!!

mars1129 [50]2 years ago

3 0

The answer is 100 inches

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you have only nicole's and dimes in your piggy bank. when you ran the coins through a change counter, it indicated you have 595

Kryger [21]

Let's say the amount of nickels you have is hmm "n"

and the amount of dimes you have is "d"

there are 5cents in one nickel, so, if "n" is the total amount of nickels you have, that means 5 * n cents or 5n

there are 10cents in one dime, so, if "d" is the total amount of dimes you have, that means 10*d or 10d

whatever 5n and 10d are, we know that their sum is 595
since the total amount the counter said you have is, only 595 cents

thus 5n + 10d = 595

solve for either, "d" or "n", and graph that

what are three likely combinations? well, just pick three points off that graph

3 0

3 years ago

Answer this!!!!!!!!!

muminat

Surface area = area of 2 triangular sides + area of the roof + area of the base.

= 2 * 1/2 * 6 * 4 + 2 * 5*7 + 6 * 7

= 24 + 70 + 42

= 136 units^2

8 0

3 years ago

The molar mass of AlCl3 is 133.34 g/mol. How many molecules of AlCl3 are there in 2 g?

Mnenie [13.5K]

To solve this problem, we have to apply mole-concept to this and we would need the molar mass of AlCl3. 2g of AlCl3 contains 9.034*10^21 molecules.

<h3>Number of Molecules in 2g of AlCl3</h3>

The molar mass of AlCl3 is given as 133.34g/mol

Data;

mass = 2g
molar mass = 133.34g/mol

Using the mole concept, we can equate the molar mass to the number of molecules present in the entity.

$133.34g = 6.023*10^2^3$

If we equate this

$133.34g = 6.023*10^2^3\\2g = x molecules\\x = \frac{2*6.023*10^2^3}{133.34} \\x = 9.034*10^2^1 molecules$

From the calculations above, 2g of AlCl3 contains 9.034*10^21 molecules.

Learn more on mole concept here;

brainly.com/question/21150359

#SPJ1

5 0

1 year ago

What the volume of the triangular prism?

klemol [59]

Idk what unit it is but it’s 80 cubic inches/feet/centimetres

6 0

2 years ago

A test consists of 10 true or false questions. To pass the test a student must answer at least eight questions correctly. If the

forsale [732]

<h3>The probability of student passing the quiz with at least 50% of the questions correct is 0.05457.</h3>

Step-by-step explanation:

Here, the total number of T/F question = 10

The minimum answers needed correctly answered = 8

So, student needs to answer at least 8 questions correctly.

Here, the possibility of answering a question correctly = $(\frac{1}{2})$ = p = 0.5

Also, the possibility of answering a question wrong = $(\frac{1}{2})$ = q = 0.5

Now, to pass he needs to answer 8 or more ( 8 , 9 or 10) answers correctly.

P(answering 8 correct answer) = $^{10}C_8(p)^8(q)^2 = ^{10}C_8(0.5)^8(0.5)^2 = 0.0439$

P(answering 9 correct answer) = $^{10}C_9(p)^9(q)^1 = ^{10}C_9(0.5)^9(0.5)^1 = 0.0097$

P(answering 10 correct answer) = $^{10}C_{10}(p)^{10}(q)^0 = ^{10}C_{10}(0.5)^{10}(0.5)^0 = 0.00097$

So, the total Probability = P(8) + P(9) + P(10)

= (0.0439) + (0.0097) + (0.00097)

= 0.05457

Hence, the probability that the student passes the quiz with at least 8 of the questions correct is 0.05457.

6 0

3 years ago