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2 years ago

Can someone help with this one too?

Mathematics

2 answers:

KIM [24]2 years ago

4 0

Answer:

the answer is C

Step-by-step explanation:

trasher [3.6K]2 years ago

3 0

Yes C is the right answer I just did that almost same question

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Order these numbers for lest to greatest 1/2 ,1.1 ,5/3 ,2, 0 ,0.4, -2 ,5/8

Nat2105 [25]

The least number should always start off with negatives if there are any. In this case there is so we can start with -2 as our least amount. Next are the small fractions. If you're allowed a calculator, I would use that to find what the decimals will look like for each fraction:

$\frac{1}{2} =0.5\\ \\ \frac{5}{3} =1.6666666666666666666666666666667\\ \\ \frac{5}{8} =0.625$

After -2 the next least number is 0 and the next one is the fraction or decimal closest to the number 0 which is 0.4

The next number would be from the fractions we solved earlier. 0.5 and 0.625 would follow 0.4 and then 1.1 and 1.6667(solved for from fraction).

Here is the list:

$-2,0,0.4,\frac{1}{2} ,\frac{5}{8} ,1.1,\frac{5}{3}$

Hope this helps!

6 0

3 years ago

Which transformations are needed to change the parent cosine function to the cosine function below? On a coordinate plane, a cur

Nastasia [14]

Answer:

vertical compression of One-half, horizontal stretch to a period of 4 pi, vertical shift of 1 unit up, phase shift of Pi units left

Step-by-step explanation:

5 0

3 years ago

The value of a house decreases at a steady rate of 20% each year. What is the total percentage loss (to the nearest integer) in

Westkost [7]

Answer: The total percentage loss would be 67%.

Step-by-step explanation:

Since we have given that

Rate of decline each year = 20%

Number of years = 5

We need to find the total percentage loss in value of the house at the end of 5 years.

So, Total percentage loss would be

$1-(1-\dfrac{r}{100})^5\\\\=1-(1-\dfrac{20}{100})^5\\\\=1-(\dfrac{4}{5})^5\\\\=1-(0.8)^5\\\\=0.67\\\\\approx 67%$

Hence, the total percentage loss would be 67%.

8 0

2 years ago

What are the coordinates of R’, the image of R(-4,3) after a reflection in the line y=x?

navik [9.2K]

Answer:

R'(3,-4)

Step-by-step explanation:

we know that

When you reflect a point across the line y = x, the x-coordinate and y-coordinate change places

The rule of the reflection across the line y=x is equal to

(x,y) ------> (y,x)

we have

R(-4,3) ------> R'(3,-4)

6 0

2 years ago

A colony of bacteria is growing at a rate of 0.2 times its mass. Here time is measured in hours and mass in grams. The mass of t

11Alexandr11 [23.1K]

Answer:

Question 1: $dm/dt=0.2m$

Question 2: $m=Ae^{(0.2t)}$

Question 3: $m=10e^{(0.2t)}$

Question 4: $m=10g$

Explanation:

Question 1: Write down the differential equation the mass of the bacteria, m, satisfies: m′= .2m

a) By definition: $m'=dm/dt$

b) Given: $rate=0.2m$

c) By substitution: $dm/dt=0.2m$

Question 2: Find the general solution of this equation. Use A as a constant of integration.

a) Separate variables

$dm/m=0.2dt$

b) Integrate

$\int dm/m=\int 0.2dt$

$ln(m)=0.2t+C$

c) Antilogarithm

$m=e^{0.2t+C}$

$m=e^{0.2t}\cdot e^C$

$e^C=A\\\\m=Ae^{(0.2t)}$

Question 3. Which particular solution matches the additional information?

Use the measured rate of 4 grams per hour after 3 hours

$t=3hours,dm/dt=4g/h$

First, find the mass at t = 3 hours

$dm/dt=0.2m\\\\4=0.2m\\\\m=4/0.2\\\\m=20g$

Now substitute in the general solution of the differential equation, to find A:

$m=Ae^{(0.2t)}\\\\20=Ae^{(0.2\times 3)}\\\\A=20/e^{(0.6)}\\\\A=10.976$

Round A to 1 significant figure:

A = 10.

Particular solution:

$m=10e^{(0.2t)}$

Question 4. What was the mass of the bacteria at time =0?

Substitute t = 0 in the equation of the particular solution:

$m=10e^{0}\\\\m=10g$

3 0

2 years ago

Can someone help with this one too?​

Can someone help with this one too?