Abcissa is x, and ordinate is y.
In this case the x is positive, and the y is negative.
Therefore, the answer is "positive, negative"
Answer:
Y = 3x^x is a graph that has exponential growth while y = 3^-x has exponential decay.
Y = 3x^x (-∞, 0) and (∞, ∞).
Y = 3x^-x (-∞, ∞) and (∞, 0).
Step-by-step explanation:
The infinity symbols were being used to represent the x and y values of each graph. I will call y = 3^x "graph 1" and y = 3^-x "graph 2".
When graph 1 had positive ∞ for its x value, its y value was reaching towards positive ∞. When its x was reaching for negative ∞, its y was going for 0.
For graph 2, however, when its x was reaching for positive ∞, its x was reaching for 0. When its x was reaching for negative ∞, its y was going for positive ∞.
Here's an image of the graphs:
Answer:
a b m n
Step-by-step explanation:
In this question (brainly.com/question/12792658) I derived the Taylor series for
about
:

Then the Taylor series for

is obtained by integrating the series above:

We have
, so
and so

which converges by the ratio test if the following limit is less than 1:

Like in the linked problem, the limit is 0 so the series for
converges everywhere.
33 * 3 + 3/3 = 100
I do not believe u have to use all of the operations because it says " at most once ".