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garik1379 [7]
3 years ago
12

(Comparable interface) Write Rectangle class that implements the Comparable interface. Override the equals method so that two Re

ctangle objects are equal if their areas are the same.
Computers and Technology
1 answer:
Ray Of Light [21]3 years ago
6 0

Answer:

class Rectangle(object):

   def __init__(self, area):

       self.area = area

   def __eq__(self,other):

       return self.area == other.area

d = Rectangle(43)

e = Rectangle(23)

print(d == e)

Explanation:

The python program defines a class called Rectangle that accepts one argument 'area' and compare one instance of the object with another instance. The '__eq__' method helps to define the equality of the instance based on their area values. If the areas are equal, the equality statement returns true and false if not.

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Two machines can finish a job in StartFraction 20 Over 9 EndFraction hours. Working​ alone, one machine would take one hour long
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<em><u>Answer</u></em>

5 hours

<em><u>Explanation</u></em>

The two working together can finish a job in

\frac{20}{9}  \: hours

Also, working alone, one machine would take one hour longer than the other to complete the same job.

Let the slower machine working alone take x hours. Then the faster machine takes x-1 hours to complete the same task working alone.

Their combined rate in terms of x is

\frac{1}{x}    +  \frac{1}{x - 1}

This should be equal to 20/9 hours.

\frac{1}{x}  +  \frac{1}{x - 1}  =  \frac{9}{20}

Multiply through by;

20x(x - 1) \times \frac{1}{x}  +20x(x - 1) \times   \frac{1}{x - 1}  =  20x(x - 1) \times \frac{9}{0}

20(x - 1)  +20x = 9x(x - 1)

20x - 20+20x = 9{x}^{2}  - 9x

9{x}^{2}  - 9x - 20x - 20x + 20= 0

9{x}^{2}  - 49x  + 20= 0

Factor to get:

(9x - 4)(x - 5) = 0

x =  \frac{4}{9}  \: or \: x = 5

It is not feasible for the slower machine to complete the work alone in 4/9 hours if the two will finish in 20/9 hours.

Therefore the slower finish in 5 hours.

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