Nina can stitch 3 of a dress in 4 hours. If drepresents the number of dresses and h represents the number of hours, which equati
on
represents this proportional relationship?
OA d=6
B.
3d=4h
oc. d = 13h
D.
d=4
OE. d=12
represents this proportional relationship?
OA d=6
B.
3d=4h
oc. d = 13h
D.
d=4
OE. d=12
1 answer:
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As the problem indicates, degrees of freedom are the number of values that can be independently selected before it is necessary to choose specific values to arrive at the desired result.
The average, on the other hand, results from the sum of a list of values divided by the amount of values in the summed list.
Assume that the mean sought is and consider that the list is composed of a single element
, in that case no random number can be selected, since the mean
must correspond to that number.
If the list were composed of two elements and
, one of the two values could be chosen randomly, and according to the chosen value the second should be the one whose sum with the previous one results in
, this given that the formula of the average
.
With three values ,
and
, it is possible to select two freely, since the thirteen must be the one that balances the sum of
, that is
.
Thus, in general, with n values, it is possible to select values freely whose sum must be balanced by the last value so that the whole sum is
.
Answer
In a list of values you can assign
values freely, that is, you have
<em>degrees of freedom.</em>
The question requires that we have to state the hypothesis:
null hypothesis;H0: u1 < u2, the alternate hypothesis;H1: u1 > u2. The one tail test is what is to be used.
<h3>A. How to state the hypothesis</h3>H0: u1 < u2
H1: u1 > u2
The one tail test statistic is what is to be used here
<h3>B. standard error </h3>= 1.49
The df = 17 + 15 - 2
= 30
test statistic = 18.9 - 17.4 / 1.49
= 1.007
We have the critical value on excel as T.INV(0.9,30)
= 1.310
E. At 0.1, we can conclude that t-value (1.007) does not lies in the rejection area. We fail to reject the null hypothesis. Hence we conclude that the mean vacation with the unlimited plan is greater.
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