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amid [387]
4 years ago
12

Y-3=2(x+1) Can you guys please help me solve for y

Mathematics
1 answer:
Tatiana [17]4 years ago
6 0

Answer:

First, you have to rewrite the question in a way to isolate your Y. This means moving the -3 over to the other side.

Y = 2(x+1) + 3

Now, you should multiply the 2 out in the parenthesis.

Y=2x+2+3

Now, combine like terms! In this case, your like terms are 2 and 3.

Y=2x + 5

Because there are no more like terms, and Y is completely isolated, Y=2x + 5 is your answer!

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\bf \textit{using the pythagorean theorem}\\\\&#10;c^2=a^2+b^2\implies \pm\sqrt{c^2-a^2}=b\qquad &#10;\begin{cases}&#10;c=hypotenuse\\&#10;a=adjacent\\&#10;b=opposite\\&#10;\end{cases}&#10;\\\\\\&#10;\pm\sqrt{5^2-(-3)^2}=b\implies \pm\sqrt{25-9}=b\implies \pm 4=b

ok... so, which is it? the +/-?   well, we also know that <span>sin(t) >0, namely that the sine of the angle is positive, so, then  is +4 then.

</span>\bf tan(\theta)=\cfrac{opposite}{adjacent}\qquad \qquad tan(t)=\cfrac{4}{-3}\implies \boxed{tan(t)=-\cfrac{4}{3}}<span>
</span>
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