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3 years ago

Y-3=2(x+1) Can you guys please help me solve for y

Mathematics

1 answer:

Tatiana [17]3 years ago

6 0

Answer:

First, you have to rewrite the question in a way to isolate your Y. This means moving the -3 over to the other side.

Y = 2(x+1) + 3

Now, you should multiply the 2 out in the parenthesis.

Y=2x+2+3

Now, combine like terms! In this case, your like terms are 2 and 3.

Y=2x + 5

Because there are no more like terms, and Y is completely isolated, Y=2x + 5 is your answer!

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3 years ago

provide a counterexample (specific values of a,b, etc. which make the statement false) for each of the following statements. Ass

ivolga24 [154]

Answer:

1. a=3, b = 2, c = 1.

2. a=2, b=3, c=4, d=6.

3. a = 9, b = 3.

Step-by-step explanation:

1. 3 | 21 is a counterexample because 3 does not divide into 2 or 1.

2. 23 | 46 is a counterexample because 2 does not divide into 3.

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2 years ago

<img src="https://tex.z-dn.net/?f=2x%5E2%2B5x%2B3%3D0" id="TexFormula1" title="2x^2+5x+3=0" alt="2x^2+5x+3=0" align="absmiddle"

melamori03 [73]

Answer:

$x=-\frac{3}{2},-1$

Step-by-step explanation:

$2x^2+5x+3=0$

Split the second term (5x) into two terms. Multiply the coefficient of the first term (2) by the constant term (3):

$2*3=6$

Find which two numbers add up to 5 and multiply into 6:

$3+2=5\\3*2=6\\3,2$

Split 5x as the sum of 3x and 2x:

$2x^2+3x+2x+3$

Now factor out a common term for the first 2 terms:

$2x^2+3x\\x(2x+3)$

And do the same for the last 2 terms:

$2x+3\\1(2x+3)$

Re-insert:

$x(2x+3)+1(2x+3)=0$

Factor out the common term 2x+3 and insert the values in front of the parentheses (x and 1):

$(2x+3)(x+1)=0$

Separate the parentheses and equal them to 0. Solve for x:

$2x+3=0\\2x+3-3=0-3\\2x=-3\\\\\frac{2x}{2}=\frac{-3}{2}\\\\ x=-\frac{3}{2}$

and

$x+1=0\\x+1-1=0-1\\x=-1$

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2 years ago

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Answer:

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1 year ago

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