Find the IQR (interquartile range). 19, 21, 18, 17, 18, 22,46
1 answer:
Answer:
4.
Step-by-step explanation:
Step 1: <u>Formula.</u>
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Step 2: <u>Explain/define.</u>
- The interquartile range is the difference between quartile 3 and quartile 1.
- Quartile 1 is the median of the upper half of a data set.
- Quartile 3 is the median of the lower half of a data set.
- The median is the 'middle value.'
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Step 3: <u>Order/arrange.</u>
In order to find the median, you must first put the numbers in numerical order.
19, 21, 18, 17, 18, 22, 46
↓
17, 18, 18, 19, 21, 22, 46
The lower half of the data set, not including the median of the whole data set, is 17, 18, and 18.
The upper half of the data set is 21, 22, and 46.
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Step 4: <u>Solve.</u>
- 17, 18, 18
- 21, 22, 36
Next, we find the medians of both sets.
The median of the lower half is 18 (Q1).
The median of the upper half is 22 (Q3).
Lastly, we subtract Q3 from Q1.
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Step 5: <u>Conclude.</u>
I, therefore, believe the interquartile range of this data set is 4.
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Answer:
Option B is correct
Left 1 unit.
Explanation:
According to the graph theory of transformation:
y = f(x+k)=
Given the parent function:
and the function
we can write it as:
g(x)= [ ∴
]
Therefore, vertex of the graph of the function is 1 units to the left of the vertex of the graph of the function
.
Answer:
(1)
(2)
The critical value for 95% of confidence interval now can be founded using the normal distribution. And in excel we can use this formla to find it:"=-NORM.INV(0.025,0,1)", and we got , replacing into formula (2) we got:
So the answer for this case would be n=25 rounded up to the nearest integer
Step-by-step explanation:
Previous concepts
A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".
The margin of error is the range of values below and above the sample statistic in a confidence interval.
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
represent the sample mean for the sample
population mean (variable of interest)
represent the population standard deviation
n represent the sample size (variable of interest)
The confidence interval for the mean is given by the following formula:
The margin of error is given by this formula:
(1)
And on this case we have that ME =0.02 and we are interested in order to find the value of n, if we solve n from equation (1) we got:
(2)
The critical value for 95% of confidence interval now can be founded using the normal distribution. And in excel we can use this formla to find it:"=-NORM.INV(0.025,0,1)", and we got , replacing into formula (2) we got:
So the answer for this case would be n=25 rounded up to the nearest integer