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aleksklad [387]
3 years ago
12

Hasil ulangan dari 15 siswa diperoleh data sebagai berikut, 8, 6, 5, 7, 8, 5, 7, 8, 7, 9, 8, 6, 9, 8, 7 , median dari data terse

but adalah …
Mathematics
1 answer:
Inessa05 [86]3 years ago
6 0
The median of this is 8.
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How do you divide 2\3 divided by 7\8 using kcf answer
xz_007 [3.2K]

Answer: \frac{16}{21}

<u>Step-by-Step Explanation:</u>

KCFmeans: Keep, Change, Flip

  • Keep: the first fraction
  • Change: the sign <em>from division to multiplication</em>
  • Flip: the second fraction

  \frac{2}{3} ÷ \frac{7}{8}

= \frac{2}{3} * \frac{8}{7}   <em>KCF is applied here!</em>

= \frac{2(8)}{3(7)}

= \frac{16}{21}



7 0
3 years ago
An industrial sewing machine uses ball bearings that are targeted to have a diameter of 0.75 inch. The lower and upper specifica
Natalija [7]

Answer:

(a) Probability that a ball bearing is between the target and the actual mean is 0.2734.

(b) Probability that a ball bearing is between the lower specification limit and the target is 0.226.

(c) Probability that a ball bearing is above the upper specification limit is 0.0401.

(d) Probability that a ball bearing is below the lower specification limit is 0.0006.

Step-by-step explanation:

We are given that an industrial sewing machine uses ball bearings that are targeted to have a diameter of 0.75 inch. The lower and upper specification limits under which the ball bearings can operate are 0.74 inch and 0.76 inch, respectively.

Past experience has indicated that the actual diameter of the ball bearings is approximately normally distributed, with a mean of 0.753 inch and a standard deviation of 0.004 inch.

Let X = <u><em>diameter of the ball bearings</em></u>

SO, X ~ Normal(\mu=0.753,\sigma^{2} =0.004^{2})

The z-score probability distribution for normal distribution is given by;

                                Z  =  \frac{X-\mu}{\sigma} } }  ~ N(0,1)

where, \mu = population mean = 0.753 inch

           \sigma = standard deviation = 0.004 inch

(a) Probability that a ball bearing is between the target and the actual mean is given by = P(0.75 < X < 0.753) = P(X < 0.753 inch) - P(X \leq 0.75 inch)

      P(X < 0.753) = P( \frac{X-\mu}{\sigma} } } < \frac{0.753-0.753}{0.004} } } ) = P(Z < 0) = 0.50

      P(X \leq 0.75) = P( \frac{X-\mu}{\sigma} } } \leq \frac{0.75-0.753}{0.004} } } ) = P(Z \leq -0.75) = 1 - P(Z < 0.75)

                                                             = 1 - 0.7734 = 0.2266

The above probability is calculated by looking at the value of x = 0 and x = 0.75 in the z table which has an area of 0.50 and 0.7734 respectively.

Therefore, P(0.75 inch < X < 0.753 inch) = 0.50 - 0.2266 = <u>0.2734</u>.

(b) Probability that a ball bearing is between the  lower specification limit and the target is given by = P(0.74 < X < 0.75) = P(X < 0.75 inch) - P(X \leq 0.74 inch)

      P(X < 0.75) = P( \frac{X-\mu}{\sigma} } } < \frac{0.75-0.753}{0.004} } } ) = P(Z < -0.75) = 1 - P(Z \leq 0.75)

                                                            = 1 - 0.7734 = 0.2266

      P(X \leq 0.74) = P( \frac{X-\mu}{\sigma} } } \leq \frac{0.74-0.753}{0.004} } } ) = P(Z \leq -3.25) = 1 - P(Z < 3.25)

                                                             = 1 - 0.9994 = 0.0006

The above probability is calculated by looking at the value of x = 0.75 and x = 3.25 in the z table which has an area of 0.7734 and 0.9994 respectively.

Therefore, P(0.74 inch < X < 0.75 inch) = 0.2266 - 0.0006 = <u>0.226</u>.

(c) Probability that a ball bearing is above the upper specification limit is given by = P(X > 0.76 inch)

      P(X > 0.76) = P( \frac{X-\mu}{\sigma} } } > \frac{0.76-0.753}{0.004} } } ) = P(Z > -1.75) = 1 - P(Z \leq 1.75)

                                                            = 1 - 0.95994 = <u>0.0401</u>

The above probability is calculated by looking at the value of x = 1.75 in the z table which has an area of 0.95994.

(d) Probability that a ball bearing is below the lower specification limit is given by = P(X < 0.74 inch)

      P(X < 0.74) = P( \frac{X-\mu}{\sigma} } } < \frac{0.74-0.753}{0.004} } } ) = P(Z < -3.25) = 1 - P(Z \leq 3.25)

                                                            = 1 - 0.9994 = <u>0.0006</u>

The above probability is calculated by looking at the value of x = 3.25 in the z table which has an area of 0.9994.

8 0
3 years ago
Urgent pls :
Luden [163]

13/52 + 13/52

26/52

1/2

0.5

50%

7 0
2 years ago
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Which equation represents a line that is perpendicular to the line with equation y=2x-8? Select all that apply
lianna [129]

Answer:

B, C, E

Step-by-step explanation:

you need to find lines whose slope is the negative reciprocal of the slope from the line you are solving for. in this case, all lines with the slope -1/2 are Perpendicular to a line with the slope of 2

8 0
2 years ago
Find the following expression by multiplying.<br><br> (a + b)^2
Hatshy [7]
You multiply it together like (a+b)(a+b)
the answer would be a^2 + 2ab + b^2
4 0
3 years ago
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