The range refers to the value of y for which x is define.
So let y=f(x),
Try making x the subject to obtain,
x is defined for all real values of y greater than
0.
Hence the correct answer is D.
Answer:
540
Step-by-step explanation:
1. We assume, that the number 900 is 100% - because it's the output value of the task.
2. We assume, that x is the value we are looking for.
3. If 900 is 100%, so we can write it down as 900=100%.
4. We know, that x is 3.5% of the output value, so we can write it down as x=3.5%.
5. Now we have two simple equations:
1) 900=100%
2) x=3.5%
where left sides of both of them have the same units, and both right sides have the same units, so we can do something like that:
900/x=100%/3.5%
6. Now we just have to solve the simple equation, and we will get the solution we are looking for.
7. Solution for what is 3.5% of 900
900/x=100/3.5
(900/x)*x=(100/3.5)*x - we multiply both sides of the equation by x
900=28.571428571429*x - we divide both sides of the equation by (28.571428571429) to get x
900/28.571428571429=x
31.5=x
x=31.5
now we have:
3.5% of 900=31.5
By using the concept of uniform rectilinear motion, the distance surplus of the average race car is equal to 3 / 4 miles. (Right choice: A)
<h3>How many more distance does the average race car travels than the average consumer car?</h3>
In accordance with the statement, both the average consumer car and the average race car travel at constant speed (v), in miles per hour. The distance traveled by the vehicle (s), in miles, is equal to the product of the speed and time (t), in hours. The distance surplus (s'), in miles, done by the average race car is determined by the following expression:
s' = (v' - v) · t
Where:
- v' - Speed of the average race car, in miles per hour.
- v - Speed of the average consumer car, in miles per hour.
- t - Time, in hours.
Please notice that a hour equal 3600 seconds. If we know that v' = 210 mi / h, v = 120 mi / h and t = 30 / 3600 h, then the distance surplus of the average race car is:
s' = (210 - 120) · (30 / 3600)
s' = 3 / 4 mi
The distance surplus of the average race car is equal to 3 / 4 miles.
To learn more on uniform rectilinear motion: brainly.com/question/10153269
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Answer:
(X<-25) or -oo, -25
Step-by-step explanation:
because max is -25
