Answer:
<em>b. At twice the distance, the electric potential is V/2</em>
Explanation:
Electric potential
Is the amount of work needed to move a unit charge from a reference point (usually a point at infinity) without producing acceleration.
The electric potential due to a point charge q at a distance r is given by
Where K is the Coulomb's constant. If we know the electric potential at a certain distance is V, if the distance is changed to 2r, then the new potential is
It means that the electric potential is half the previous value. Correct option: b.
Need Height and Mass, since Gravitational Potential Energy is equal to mgh. Not really sure what you’re asking though. Please elaborate and I can give a better answer!
Specific heat = Heat / (mass x change in temperature)
specific heat= 2.34 x 10^3 / 200 x 30
specific heat = 2,340 / 6,000
Specific Heat= 0.39<span>
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A. long-wave radiation occupies a smaller percentage than short-wave radiation
The initial velocity of particle is 7.568 m/s
Given:
Acceleration = a = 6.14 m/s2
Time = t = 0.300 s.
final velocity = v = 9.41 m/s.
To Find:
initial velocity = u
Solution: Velocity is the prime indicator of the position as well as the rapidity of the object.
v = u + at
u = v - at = 9.41 - 6.14*0.3 = 7.568 m/s
Hence, initial velocity of particle is 7.568 m/s
Learn more about Velocity here:
brainly.com/question/25749514
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