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EleoNora [17]
4 years ago
8

The earth makes ( ) around the sun in it's ( )

Physics
1 answer:
Stella [2.4K]4 years ago
6 0
(Rotations and orbit)
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Water is flowing in a fire hose with a velocity of 1.0 m/s and a pressure of 200000 Pa. At the nozzle the pressure decreases to
jeka57 [31]

Answer:

The velocity is v_n  =14.09 \ m/s

Explanation:

From the question we are told that

    The velocity of the water in the pipe is  v_i =  1.0 \ m/s

     The pressure inside the pipe  is  P_i  = 200000 \ Pa

      The pressure at the nozzle is  P_n  =  101300 \ Pa

       The density of water is  \rho  =  1000 \ kg / m^3

      For the height h_1 = h_2 = h

where  h_1 is height of water in the pipe

  and  h_2 is height of water at the nozzle

Generally Bernoulli equation is represented as

       \frac{1}{2} \rho * v_i ^2 + \rho * g * h_1 +  P_i =  \frac{1}{2} \rho v_n ^2 + \rho * g* h_2 + P_n

=>   \frac{1}{2} \rho * v_i ^2 + \rho * g * h +  P_1 =  \frac{1}{2} \rho v_n ^2 + \rho * g* h + P_2

Where v_n is the velocity of the water at the nozzle

Now  making  v_n  the subject

            v_n  =  \sqrt{\frac{2}{\rho} [ P_i - Pn + \frac{1}{2} \rho v_i^2}

substituting values

            v_n  =  \sqrt{\frac{2}{1000} [ 200000 - 101300 + \frac{1}{2} (1000 * (1.0)^2)}

           v_n  =14.09 \ m/s

     

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Could you please assist me, thank you kindly.
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In Newton's Third law of motion, the 'action' and 'reaction' forces act on different objects.  That's why they don't cancel each other out and always result in zero force.

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