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Finger [1]
3 years ago
15

What is the distance in units from (2, -12) to (-11, -12) 20 POINTSSS HURRY PLEASEEEE

Mathematics
2 answers:
Zinaida [17]3 years ago
5 0

Answer:

Distance =\sqrt{(-11-2)^2 + (-12+12)^2}

Distance = \sqrt{(-13)^2}

Distance = 13 units

sweet [91]3 years ago
3 0

Answer:

d= (-11-2)^2 + (-12--12)^2

d= (-13)^2 + (0)^2

d=169

square root the 169

answer is 13

that's the distance from (2, -12) (-11, -12)

hope that helps

Step-by-step explanation:

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An engineer scale model shows a building that is 3 inches tall. If the scale is 1 inch = 600 feet, how tall is the actual buildi
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The actual height of building is 1800 feet.

Step-by-step explanation:

Given,

Height of building in model = 3 inches

Scale used by engineer;

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Actual height of building = Height in model * Scale used

Actual height of building = 3 * 600

Actual height of building = 1800 feet

The actual height of building is 1800 feet.

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3 years ago
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3 years ago
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90 Minutes

Step-by-step explanation:

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7 0
2 years ago
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A researcher computes the following 2 x 3 between-subjects ANOVA, in which 11 participants were observed in each group. Which ef
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Answer:

D. There were no significant effects.

Step-by-step explanation:

The table below shows the representation of the significance level using the two-way between subjects ANOVA.

Source of Variation            SS          df          MS          F                P-value

Factor A                             10          1              10           0.21           0.660

Factor B                             50         2             25          0.52          0.6235  

     

A × B                                  40          2             20         0.42           0.6783

Error                                   240        5             48           -               -

Total                                   340       10             -             -                  -

From the table above , the SS(B) is determined as follows:

SS(B) = SS(Total)-SS(Error-(A×B)-A)

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         = 50

A researcher computes the following 2 x 3 between-subjects ANOVA;

k=2

n=3

N(total) = no of participants observed in each group =11

df for Factor A= (k-1)

=(2-1)

=1

df for Factor B = (n-1)

=(3-1)

=2

df for A × B    

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df  factor for total

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MS = SS/df

Thus, from the table, the P-Value for all data is greater than 0.05, therefore we fail to reject H₀.

4 0
3 years ago
What math concepts are important in solving the problem
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Answer:

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Step-by-step explanation:

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