Answer:
0.1225
Step-by-step explanation:
Given
Number of Machines = 20
Defective Machines = 7
Required
Probability that two selected (with replacement) are defective.
The first step is to define an event that a machine will be defective.
Let M represent the selected machine sis defective.
P(M) = 7/20
Provided that the two selected machines are replaced;
The probability is calculated as thus
P(Both) = P(First Defect) * P(Second Defect)
From tge question, we understand that each selection is replaced before another selection is made.
This means that the probability of first selection and the probability of second selection are independent.
And as such;
P(First Defect) = P (Second Defect) = P(M) = 7/20
So;
P(Both) = P(First Defect) * P(Second Defect)
PBoth) = 7/20 * 7/20
P(Both) = 49/400
P(Both) = 0.1225
Hence, the probability that both choices will be defective machines is 0.1225
Answer:
Yes
Step-by-step explanation:
Multiply 4/5 so that they have a common denominator.
14/15 > 12/15 (4/5)
Answer:
a.) one sample t test
b.) H0 : μ = 59.3
c.) H1 : μ > 59.3
d.) μ = 59.3 ; σ = 39.84
e.) xbar = 79.4 ; s = 61.36
Test statistic = 3.16
Step-by-step explanation:
Given the sample data:
49.00 49.00 49.00 49.00 49.00 63.00 63.00 63.00 63.00 63.00 199.00 199.00 199.00 199.00 199.00 38.00 38.00 38.00 38.00 38.00 48.00 48.00 48.00 48.00 48.00 49.00 63.00 199.00 38.00 48.00
Sample size, n = 30
Using calculator :
xbar from the data above = 79.4
Standard deviation = 61.359
H0 : μ = 59.3
H1 : μ > 59.3
Test statistic :
(Xbar - μ) ÷ (σ/sqrt(n)
σ = 34.83
(79.4 - 59.3) ÷ (34.83/sqrt(30))
20.1 ÷ 6.359
Test statistic = 3.16
Answer:
8 and 19
Step-by-step explanation:
To some this, let's first list all the factors of 152. They are;
1, 2, 4, 8, 19, 38, 76, 152.
Now, let's arrange them to reflect being multiplied to get 152.
Thus;
1 × 152 = 152
2 × 76 = 152
4 × 38 = 152
8 × 19 = 152
Also, let's do the same for their sum;
1 + 152 = 153
2 + 76 = 78
4 + 38 = 42
8 + 19 = 27
Looking at the figures above, the ones that their product is 152 but have the least sum are 8 and 19
First, multiply 4*2x-4*-5= 8x-20.
Second, add 15 to 8x-20
Third, that would equal 8x-20+15=11
Fourth, 15+-20= -5
Fifth, 8x-5=11
Sixth, add +5 to -5 and +5 to 11= 8x=16
Last, do 8x/8x and 16/8x
The answer is x=2
