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miskamm [114]
2 years ago
12

A paper container in the shape of a right circular cone has a radius of 3 inches and a height of 8 inches. Determine and state t

hr number of cubic inches in the volume of the cone, in terms of  π.​

Mathematics
1 answer:
Scrat [10]2 years ago
7 0

Given:

Radius of the cone = 3 inches

Height of the cone = 8 inches

To find:

The volume of the cone, in terms of  π.​

Solution:

We know that, the volume of a cone is:

V=\dfrac{1}{3}\pi r^2h

Putting r=3,h=8, we get

V=\dfrac{1}{3}\pi (3)^2(8)

V=\dfrac{1}{3}\pi (9)(8)

V=\dfrac{72}{3}\pi

V=24\pi

Therefore, the volume of the cone is 24\pi.

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Answer:

3.04m

Step-by-step explanation:

Time taken to swing the rope = 3.5s

Length of the rope = L

T = 2π√(L / 9.8)

3.5 = 2π√(L / 9.8)

take the square of both sides

(3.5)² =[2π√(L/9.8)]²

12.25 = 39.48 × (L / 9.8)

12.25 = 39.48L / 9.8

39.48L = 12.25 × 9.8

39.48L = 120.05

L = 120.05 / 39.48

L = 3.04m

The length of the rope is 3.04m

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3 years ago
Which equations are equivalent to Three-fourths + m = negative StartFraction 7 over 4 EndFraction? Select three options.
sammy [17]

Answer:

Feb 28, 2020 — ... EndFraction? Select all that apply. ... X = StartFraction 6 over 4 EndFraction x = Negative StartFraction 6 over 4 EndFraction x minus one-fourth = negative StartFraction 5 over 4 EndFraction x = negative three-halves x = negative three-fourths. 2 ... Ashley solved the equation for m using the following steps.

2 answers

 

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Top answer:  

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3 years ago
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Which of the following sentences is true? a. 6.3 is less than 6.2. b. 6.8 is greater than 6.5. c. 6.6 is less than 6.0. d. 6.4 i
r-ruslan [8.4K]
<span>b. 6.8 is greater than 6.5.    
This is the true sentence</span>
4 0
3 years ago
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Which of these is a number that can be expressed as a non-repeating, nonterminating decimal?
mylen [45]

Answer:

A. An irrational number

D. A fraction

Step-by-step explanation:

Nonrepeating numbers are number/decimal that continues endlessly with no set of numbers alike or repeating theirself

while nonterminating numbers are numbers that do not have an end

examples can be a fraction, irrational numbers

6 0
2 years ago
What is the following quotient?
mamaluj [8]

Answer:

A.2(3^{\frac{1}{3}})-\sqrt[3]{18}

Step-by-step explanation:

We are given that

\frac{6-3(\sqrt[3]{6}}{\sqrt[3]{9}})

We have to find the quotient.

\frac{6}{\sqrt[3]{9}}-3(\frac{\sqrt[3]{6}}{\sqrt[3]{9}})

\frac{2\times 3}{\sqrt[3]{3^2}}-3(\frac{\sqrt[3]{3\times 2}}{\sqrt[3]{3^2}})

2\times\frac{3}{3^{\frac{2}{3}}}-3(\frac{2^{\frac{1}{3}}\times 3^{\frac{1}{3}}}{3^{\frac{2}{3}}})

Using the property

(ab)^n=a^n\cdot b^n

2\times 3^{1-\frac{2}{3}}-3(2^{\frac{1}{3}}\times 3^{\frac{1}{3}-\frac{2}{3}})

Using the property

\frac{a^x}{a^y}=a^{x-y}

2(3^{\frac{1}{3}})-3(2^{\frac{1}{3}}\times 3^{-\frac{1}{3}})

2(3^{\frac{1}{3}})-2^{\frac{1}{3}}\times 3^{1-\frac{1}{3}}

2(3^{\frac{1}{3}})-2^{\frac{1}{3}}\times 3^{\frac{2}{3}}

2(3^{\frac{1}{3}})-2^{\frac{1}{3}}\times \sqrt[3]{3^2}

2(3^{\frac{1}{3}})-2^{\frac{1}{3}}\times \sqrt[3]{9}

2(3^{\frac{1}{3}})-\sqrt[3]{2\times 9}

2(3^{\frac{1}{3}})-\sqrt[3]{18}

Hence, the quotient of \frac{6-3(\sqrt[3]{6}}{\sqrt[3]{9}}) is given by

2(3^{\frac{1}{3}})-\sqrt[3]{18}

Option A is correct.

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2 years ago
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