2. CuCl₂·2H₂O is limiting reactant.
Chemical reaction: 3CuCl₂·2H₂O + 2Al → 3Cu + 2AlCl₃ + 6H₂O. m(Al) = 0,5 g.
Answer is: mass number of element is 234.
<span>Alpha particle is nucleus of a </span>helium-4<span> atom, which is made of two </span>protons<span> and two </span>neutrons<span>.
</span>²³⁸U → ²³⁴Th + α (alpha particle).
Alpha decay is radioactive decay<span> in which an </span>atomic nucleus<span> emits an </span>alpha particle<span> (helium nucleus) and transforms into an atom with </span>an atomic number that is reduced by two <span>and </span>mass number<span> that is reduced by four</span><span>.</span>
<h3>
Answer:</h3>
0.90J/g°C
<h3>
Explanation:</h3>
We are given:
Mass of Aluminium = 10 g
Quantity of heat = 677 Joules
Change in temperature = 125°C - 50°C
= 75°C
We are required to calculate the specific heat capacity of Aluminium
But, Quantity of heat = Mass × specific heat × Change in temperature
Q = mcΔt
Rearranging the formula;
c = Q ÷ mΔt
= 677 J ÷ (10 g × 75°C)
= 677 J ÷ 750g°C
= 0.903 J/g°C
= 0.90J/g°C
Thus, the specific heat capacity of Aluminium is 0.90J/g°C
Answer:
A I believe is your best choice.
Explanation:
