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Schach [20]
4 years ago
6

Uranium-238 decays by alpha emission. what is the mass number of the resulting element? express your answer numerically as an in

teger.
Chemistry
1 answer:
vredina [299]4 years ago
4 0
Answer is: mass number of element is 234.
<span>Alpha particle is nucleus of a </span>helium-4<span> atom, which is made of two </span>protons<span> and two </span>neutrons<span>.
</span>²³⁸U → ²³⁴Th + α (alpha particle).
Alpha decay is radioactive decay<span> in which an </span>atomic nucleus<span> emits an </span>alpha particle<span> (helium nucleus) and transforms into an atom with </span>an atomic number that is reduced by two <span>and </span>mass number<span> that is reduced by four</span><span>.</span>

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4 years ago
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5 0
3 years ago
80 POINTS!! Will mark brainliest if answer is correct with all work shown.
Stella [2.4K]

Answer:

536 grams

The balanced equation is Ba + 2 HBr ==> BaBr2 + H2, so that indicates that mole of Ba will react with 2 moles of HBr. So let's determine how many moles of HBr we have and from there, determine the number of moles of Ba needed and the mass of that much Ba. The number of moles of HBr is simply the product of volume of solution used and its molarity. So:

1.30 L * 6.00 mol/L = 7.80 mol

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3 years ago
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