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olya-2409 [2.1K]
3 years ago
14

A racecar accelerates uniformly from 18.5 mil to 46.1 m/s in 2.47 seconds.

Physics
1 answer:
laiz [17]3 years ago
5 0

Answer:

<em>The acceleration of the racecar is</em> \mathbf{11.17~m/s^2}

Explanation:

<u>Uniformly Accelerated Motion</u>

It's a type of motion in which the velocity of an object changes by an equal amount in every equal period of time.

Following the definition above, the acceleration is defined as:

\displaystyle a=\frac{v_f-v_o}{t}

Where a is the constant acceleration, vo the initial speed, vf the final speed, and t the time.

The racecar goes from vo=18.5 m/s to vf=46.1 m/s in t=2.47 seconds, thus the acceleration is:

\displaystyle a=\frac{46.1-18.5}{2.47}

\displaystyle a=\frac{27.6}{2.47}

a = 11.17~m/s^2

The acceleration of the racecar is \mathbf{11.17~m/s^2}

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