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jeka57 [31]
2 years ago
6

What Type Of Technologies are helping reduce ozone?

Physics
1 answer:
atroni [7]2 years ago
4 0

Sector-specific technological measures – vapor recovery nozzles at gasoline pumps, cleaner-burning fuels, strong vehicle inspection programs and strict emission limits for refineries, industrial emissions and combustion sources – all can help control ozone pollution and have contributed to lower emissions over the last three decades

hope this helps

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In 1986, several robotic spacecrafts were sent into space to study the Halley's Comet. Which of these statements best explains w
maks197457 [2]
No spacecraft has been built yet that was able to absorb harmful
radiations in space, change weather conditions on Earth, or destroy
meteors and comets which might strike Earth.

We should continue to send robotic spacecrafts into space
because they help discard some myths about objects in space. 
In other words, they help us learn things that we never knew before.

4 0
3 years ago
What happens when the crests of two waves overlap
gregori [183]
Energy of the waves are redistributed to form a resultant wave with amplitude given by the summation of individual wave's amplitude. 
<span>If the two waves are of same frequency, speed and amplitude and travelling in opposite direction den stationary waves are form.</span>
4 0
3 years ago
Plz answer this very soon
tester [92]

Answer:

Im gonna say it is answer A:) Hope this helps!

Explanation:

6 0
3 years ago
Read 2 more answers
Whats the answer???????????
Leviafan [203]

Answer: Less than 4 ohms

Explanation:

We have three resistors with the following resistance:

R_{1}=4\Omega

R_{2}=6\Omega

R_{3}=8\Omega

Now, when the resistors are connected in parallel, the total resistance R is calculated as follows:

\frac{1}{R}=\frac{1}{R_{1}}+\frac{1}{R_{2}}+\frac{1}{R_{3}}

Isolating R:

R=\frac{R_{1}R_{2}R_{3}}{R_{3}(R_{1}+R_{2})+R_{1}R_{2}}

Rewriting with th known values:

R=\frac{(4\Omega)(6\Omega)(8\Omega)}{8\Omega(4\Omega+6\Omega)+(4\Omega)(6\Omega)}

Finally:

R=1.84 \Omega

Hence, the correct option is less than 4 ohms.

4 0
3 years ago
The de broglie wavelength of an electron with a velocity of 6.00 × 106 m/s is ________ m. The mass of the electron is 9.11 × 10-
WINSTONCH [101]

Answer: 1.212(10)^{-10} m

Explanation:

The de Broglie wavelength \lambda is given by the following formula:

\lambda=\frac{h}{p} (1)

Where:

h=6.626(10)^{-34}\frac{m^{2}kg}{s} is the Planck constant

p is the momentum of the atom, which is given by:

p=m_{e}v (2)

Where:

m_{e}=9.11(10)^{-28}g=9.11(10)^{-31}kg is the mass of the electron

v=6(10)^{6}m/s is the velocity of the electron

This means equation (2) can be written as:

p=(9.11(10)^{-31}kg)(6(10)^{6}m/s) (3)

Substituting (3) in (1):

\lambda=\frac{6.626(10)^{-34}\frac{m^{2}kg}{s}}{(9.11(10)^{-31}kg)(6(10)^{6}m/s)} (4)

Now, we only have to find \lambda:

\lambda=1.2122(10)^{-10} m>>> This is the de Broglie wavelength of the electron

8 0
3 years ago
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