A. The magnitude of the spring force (in N) acting upon the object is 15.9 N
B. The magnitude of the object's acceleration (in m/s²) is 30.58 m/s²
C. The direction of the acceleration vector points toward the equilibrium position (i.e., to the left in the figure).
<h3>A. How to determine the force </h3>
- Extension (e) = 0.150 m
- Spring constant (K) = 106 N/m
- Force (F) = ?
F = Ke
F = 106 × 0.15
F = 15.9 N
<h3>B. How to determine the acceleration</h3>
- Mass (m) = 0.52 Kg
- Force (F) = 15. 9 N
- Acceleration (a) =?
F = ma
Divide both sides by m
a = F / m
a = 15.9 / 0.52
a = 30.58 m/s²
<h3>C. How to determine the direction of the acceleration vector</h3>
Considering the diagram, we can see that the spring was pulled away from the equilibrium point.
Thus, when the spring is released, it will move toward the equilibrium point. This is also true about the acceleration.
Therefore, we can conclude that the direction of the acceleration vector is towards the equilibrium point.
Learn more about spring constant:
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Answer:
1768 N
Explanation:
We can solve the problem by using Newton's second law:
where
F is the net force acting on an object
m is the mass of the object
a is its acceleration
In this problem, we have a car of mass
m = 884 kg
And its acceleration is
Substituting into the equation, we find the net force on the car:
Answer:
a) The force is zero, or the displacement is zero, or the angle is 180 degrees
b) The kinetic energy, speed, and velocity of the particle change.
c) W1 = - W2
Answer:
A
Explanation: This isn't Physics, but there's your answer.
