Answer:
2354.4 Pa
40221 Pa
Explanation:
= Density = 1000 kg/m³
g = Acceleration due to gravity = 9.81 m/s²
h = Depth
The pressure difference would be
![\Delta P=\rho gh\\\Rightarrow \Delta P=1000\times 0.24\times 9.81\\\Rightarrow \Delta P=2354.4\ Pa](https://tex.z-dn.net/?f=%5CDelta%20P%3D%5Crho%20gh%5C%5C%5CRightarrow%20%5CDelta%20P%3D1000%5Ctimes%200.24%5Ctimes%209.81%5C%5C%5CRightarrow%20%5CDelta%20P%3D2354.4%5C%20Pa)
The pressure difference in the first case is 2354.4 Pa
![\Delta P=\rho gh\\\Rightarrow \Delta P=1000\times 4.1\times 9.81\\\Rightarrow \Delta P=40221\ Pa](https://tex.z-dn.net/?f=%5CDelta%20P%3D%5Crho%20gh%5C%5C%5CRightarrow%20%5CDelta%20P%3D1000%5Ctimes%204.1%5Ctimes%209.81%5C%5C%5CRightarrow%20%5CDelta%20P%3D40221%5C%20Pa)
The pressure difference in the second case is 40221 Pa
Since two identical bulbs are connected in this circuit in series combination
So here same current will flow into the circuit
So here we can say
![V = V_1 + V_2](https://tex.z-dn.net/?f=V%20%3D%20V_1%20%2B%20V_2)
![V = 3 volts](https://tex.z-dn.net/?f=V%20%3D%203%20volts)
also we know that
![V_1 = iR_1](https://tex.z-dn.net/?f=V_1%20%3D%20iR_1)
![V_2 = iR_2](https://tex.z-dn.net/?f=V_2%20%3D%20iR_2)
also it is given that bulbs are identical so we have
![V_1 = V_2](https://tex.z-dn.net/?f=V_1%20%3D%20V_2)
as we have
![R_1 = R_2](https://tex.z-dn.net/?f=R_1%20%3D%20R_2)
so now we can say
![V = 2V_{CD}](https://tex.z-dn.net/?f=V%20%3D%202V_%7BCD%7D)
![3 = 2V_{CD}](https://tex.z-dn.net/?f=3%20%3D%202V_%7BCD%7D)
![V_{CD} = 1.5 Volts](https://tex.z-dn.net/?f=V_%7BCD%7D%20%3D%201.5%20Volts)
so here voltage across C and D is 1.5 volts
Answer:
you couldn't do this on your own or search it up on google
Answer:
A & B are correct
Explanation:
Certain automotive sensors like crank shaft position sensor uses a.c. while most automotive components require DC to work properly through the battery which is incorporated with an alternator to keep it charged through a diode while continual supply of DC is sustained.