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cestrela7 [59]
2 years ago
12

In PQR the measure of R=90, QR=61 feet and RP=90 find the measure of P to the nearest degree.

Mathematics
1 answer:
Slav-nsk [51]2 years ago
7 0

Answer:

<P = 56 degrees

Step-by-step explanation:

Given the following

m<R = 90 degrees

QR = 61feet = Adjacent

RP = 90 feet= Opposite

Required

tan<P = opp/adj

Tan<P = 90/61

<P = arc tan (90/61)

<P = arctan 1.4754

<P = 55.9

<P = 56 degrees to the nearest degree

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2 years ago
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Use Polya's four-step problem-solving strategy and the problem-solving procedures presented in this lesson to solve the followin
svp [43]

Answer:

a) 1+2+3+4+...+396+397+398+399=79800

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Step-by-step explanation:

We know that a summation formula for the first n natural numbers:

1+2+3+...+(n-2)+(n-1)+n=\frac{n(n+1)}{2}

We use the formula, we get

a) 1+2+3+4+...+396+397+398+399=\frac{399·(399+1)}{2}=\frac{399· 400}{2}=399· 200=79800

b) 1+2+3+4+...+546+547+548+549=\frac{549·(549+1)}{2}=\frac{549· 550}{2}=549· 275=150975

c)2+4+6+8+...+72+74+76+78=S / ( :2)

1+2+3+4+...+36+37+38+39=S/2

\frac{39·(39+1)}{2}=S/2

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2+4+6+8+...+72+74+76+78=1560

5 0
3 years ago
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evablogger [386]

Answer:

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Step-by-step explanation:

Data

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For this problem:

                             3  | -2  0 |   =    | (-2 x 3)     (0 x 3) |

                                 |  4 -7  |         | (4 x 3)      (-7 x 3) |

                                               =    | -6     0 |

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3 years ago
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cluponka [151]

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