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LiRa [457]
3 years ago
10

A certain coin is a circle with diameter 18 mm. What is the exact area of either face of the coin? The exact årea of either face

of the coin is mm2. (Simplify your answer. Type an exact answer in terms of re.)​
Mathematics
1 answer:
solniwko [45]3 years ago
7 0

I don't understand it sorry

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Rewrite in standard form identify the degree of the polynomial and the number of terms
Alenkasestr [34]

Standard Form: ax² + bx + c = y

Basically, you put all the numbers from greatest to least with exponents then variables.

We have the numbers:

9

-x²

2x^5

-7x

Put these numbers from least to greatest from the exponents.

2x^5 - x² - 7x + 9

The degree of the polynomial is the number with the greatest exponent. In this case, the highest exponent is 5.

The degree of the polynomial is 5.

Best of Luck!

7 0
3 years ago
\dfrac {15}k
Monica [59]

Answer:

5

Step-by-step explanation:

8 0
3 years ago
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Find an equation of the line l that passes through the point (x, y) = (−9, 2) and satisfies the condition. the x-intercept of l
spayn [35]
-9(2)+4=-16 you do -9 times 2 which is -18 then you subtract that to 4 which you get -16. hope this helps!

3 0
3 years ago
If f(x)=2x^2+(1000/x), find the average rate of change of f(x) from x=a to x=a+h.
galina1969 [7]

Answer:

\frac{\frac{1000}{x+h}-\frac{1000}{x}}{h} is your average rate of change,

Step-by-step explanation:

average rate of change is

\frac{f(a+h)-f(a)}{a+h-a}, by slope formula

simplify this to get \frac{f(a+h)-f(a)}{h}, which is the definition of the derivative as h goes to 0

\lim_{h \to 0} \frac{f(a+h)-f(a)}{h}

since you defined x=a, we can substitute a for x and vice versa to find our derivative.

\lim_{h \to 0} \frac{(2x^2+\frac{1000}{x+h})-(2x^2+\frac{1000}{x})}{h}

simplifying

\lim_{h \to 0} \frac{\frac{1000}{x+h}-\frac{1000}{x}}{h} (your average rate of change)

6 0
3 years ago
When is A divided by B equal to an integer? Explain please.
Evgen [1.6K]
Can't see all the options. 

However, I'll guess and suggest B.

Not sure if this helped at all :P
6 0
4 years ago
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