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jeka57 [31]
3 years ago
14

What is the horizontal asymptote for the above function? y= x^2 / x^2 -9

Mathematics
1 answer:
soldier1979 [14.2K]3 years ago
5 0

23

Step-by-step explanation:

aoajwjwjwjwjwheehejeheeheheheheheueheuehehehehejheheehhejeueh3hjjjhh

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Given that sin theta = 1/4, 0
GaryK [48]
Answer: cos(Θ) = (√15) / 4

Explanation:

The question states:

1) sin(Θ) = 1/4

2) 0 < Θ < π / 2

3) find cos(Θ)

This is how you solve it.

1) Use the fundamental identity (in this part I use α instead of Θ, just for facility of wirting the symbols, but they mean the same for the case).

(cos \alpha )^2 + (sin \alpha )^2 =1

2) From which you can find:

(cos \alpha )^2 = 1 - (sin \alpha )^2

3) Replace sin(α) with 1/4

=> (cos \alpha )^2 = 1 - (1/4)^2 = 1 - 1/16 = 15/16

=> cos \alpha =+/- \sqrt{15/16} = +/- (\sqrt{15} )/4

4) Given that the angle is in the first quadrant, you know that cosine is positive and the final answer is:

cos(Θ) = \sqrt{15} /4.

And that is the answer.
6 0
4 years ago
What is the square of 7
kkurt [141]
2.64575131106 I don’t know if you need to round the answer or not
6 0
3 years ago
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(9, 18)and<br> (3, n) .<br> Find<br> n
Maru [420]

I don't seem to comprehend what you are asking?

8 0
3 years ago
Factor the polynomial.<br> 13x² – 20x – 12
erma4kov [3.2K]

Answer:

(13 x + 6) (x - 2)

Step-by-step explanation:

Factor the following:

13 x^2 - 20 x - 12

Factor the quadratic 13 x^2 - 20 x - 12. The coefficient of x^2 is 13 and the constant term is -12. The product of 13 and -12 is -156. The factors of -156 which sum to -20 are 6 and -26. So 13 x^2 - 20 x - 12 = 13 x^2 - 26 x + 6 x - 12 = x (13 x + 6) - 2 (13 x + 6):

x (13 x + 6) - 2 (13 x + 6)

Factor 13 x + 6 from x (13 x + 6) - 2 (13 x + 6):

Answer: (13 x + 6) (x - 2)

6 0
4 years ago
HELP!!!!
egoroff_w [7]

Answer:

x axis

Step-by-step explanation:

5 0
3 years ago
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