Question

One of the legs of a right triangle measures 9 cm and the other leg measures 11 cm.

Answer 1

Answer:

$\boxed {\boxed {\sf 14.2 \ cm}}$

Step-by-step explanation:

Since this is a right triangle, we can use the Pythagorean Theorem to solve for the sides.

$a^2+b^2=c^2$

where a and b are the legs and c is the hypotenuse. In this triangle, we know the legs are 9 centimeters and 11 centimeters, or:

• a= 9 cm
• b= 11 cm

Substitute these values into the formula.

$(9 \ cm)^{2} +(11 \ cm)^{2} =c^{2}$

Solve the exponents.

• (9 cm)²= 9 cm*9 cm=81 cm²

$81 \ cm^{2} +(11 \ cm)^{2} =c^{2}$

• (11 cm)²= 11 cm*11 cm= 121 cm²

$81 \ cm^{2} +121 cm^{2} =c^{2}$

Add the values on the left side.

$202 \ cm^{2} =c^{2}$

Since we are solving for c, we must isolate the variable. It is being squared and the inverse of a square is the square root. Take the square root of both sides.

$\sqrt {202 \ cm^{2} }=\sqrt{c^{2} }$

$\sqrt {202 \ cm^{2} }=c$

$14.2126704036 \ cm =c$

We are told to round to the nearest tenth.

• 14.2126704036

The 1 in the hundredth place tells us to leave the 2 in the tenth place.

$14.2 \ cm= c$

The hypotenuse is equal to 14.2 centimeters.