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3 years ago

If we increase the distance traveled when doing work, and keep all other factors the same, what will happen?

Physics

1 answer:

stepladder [879]3 years ago

8 0

Answer: D

Explanation:

A -amount of work

F-force

s-distance

If you keep same Force(F) and increase distance(s), amount of work will increase, according to:

A=F*s

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Do this work if someone give correct answer I make her brainliest do this worksheet please

Stella [2.4K]

Answer:

ok send the work so that I can do it

3 0

2 years ago

Read 2 more answers

1. How much energy would be required to melt 450 grams of ice at 0°C?

xenn [34]

Answer:

Explanation:

1. The amount of heat needed to melt ice at 0°C is equal to the mass of the ice times the latent heat of fusion.

q = mL

q = (450 g) (334 J/g)

q = 150,300 J

q = 150 kJ

2. The amount of heat released by the condensation of steam at 100°C is equal to the mass of the steam times the latent heat of vaporization.

q = mL

q = (325 g) (2260 J/g)

q = 734,500 J

q = 735 kJ

3. q = mL

q = (85 g) (2260 J/g)

q = 192,100 J

q = 190 kJ

4. q = mL

q = (225 g) (334 J/g)

q = 75,150 J

q = 75.2 kJ

5. Above 100°C, water is steam. The amount of heat needed to increase the temperature of steam is equal to its mass times its specific heat times the change in temperature.

q = mCΔT

q = (20.0 g) (2.03 J/g/°C) (303.0°C − 283.0°C)

q = 812 J

6. q = mCΔT

q = (15.0 g) (2.03 J/g/°C) (250.0°C − 275.0°C)

q = -761 J

7. q = mCΔT

q = (10.0 g) (0.90 J/g/°C) (55°C − 22°C)

q = 297 J

8. q = mCΔT

198 J = (55.0 g) C (15°C)

C = 0.24 J/g/°C

9. q = mCΔT

41,840 J = m (4.184 J/g/°C) (28.5°C − 22.0°C)

m = 1540 g

10. q = mCΔT

q = (193 g) (2.46 J/g/°C) (35°C − 19°C)

q = 7600 J

11. First, the temperature of the ice must be raised to 0°C.

q = mCΔT

q = m (2.09 J/g/°C) (0°C − (-23.0°C))

q/m = 48.1 J/g

Next, the ice must be melted.

q = mL

q/m = 334 J/g

Then, the water must be heated to 100°C.

q = mCΔT

q = m (4.184 J/g/°C) (100°C − 0°C)

q/m = 418.4 J/g

The water is then vaporized.

q = mL

q/m = 2260 J/g

Finally, the steam is heated to its final temperature.

q = mCΔT

q = m (2.03 J/g/°C) (118°C − 100°C)

q/m = 36.5 J/g

So the total amount of energy needed is:

q/m = 48.1 J/g + 334 J/g + 418.4 J/g + 2260 J/g + 36.5 J/g

q/m = 3100 J/g

3 0

2 years ago

Neglecting air resistance, when does a struck baseball accelerate downward at a rate of 9.8 m/s2?

olga2289 [7]

A baseball is accelerated downward at 9.8 m/s^2 when the only vertical force acting upon the baseball is gravity.

3 0

3 years ago

Read 2 more answers

A rocket is fired at 100 m/s at an angle of 37, how many seconds did it take to get to the top?

Kobotan [32]

Answer:

6.14 s

Explanation:

The time the rocket takes to reach the top is only determined from its vertical motion.

The initial vertical velocity of the rocket is:

$u_y = u sin \theta = (100)(sin 37^{\circ})=60.2 m/s$

where

u = 100 m/s is the initial speed

$\theta=37^{\circ}$ is the angle of launch

Now we can apply the suvat equation for an object in free-fall:

$v_y = u_y +gt$

where

$v_y$ is the vertical velocity at time t

$g=-9.8 m/s^2$ is the acceleration of gravity

The rocket reaches the top when

$v_y =0$

So by substituting into the equation, we find the time t at which this happens:

$t=-\frac{u_y}{g}=-\frac{60.2}{-9.8}=6.14 s$

7 0

3 years ago

If wheel turning at a constant rate completes 100 revolutions in 10 s its angular speed is:

GenaCL600 [577]

The frequency of the wheel is given by:
$f= \frac{N}{t}$
where N is the number of revolutions and t is the time taken. By using N=100 and t=10 s, we find the frequency of the wheel:
$f= \frac{100}{10 s}=10 s^{-1}$

And now we can find the angular speed of the wheel, which is related to the frequency by:
$\omega=2 \pi f=2 \pi (10 s^{-1})=62.8 s^{-1}$

6 0

3 years ago