If we increase the distance traveled when doing work, and keep all other factors the same, what will happen?
1 answer:
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Answer:
The work done is 5136.88 J.
Explanation:
Given that,
n = 1.90 mol
Temperature = 296 K
If the initial volume is V then the final volume will be V/3.
We need to calculate the work done
Using formula of work done
Put the value into the formula
The Work done on the system.
Hence, The work done is 5136.88 J.
The rate at which the height is changing is ( 5 / x ) m / hr
We know that,
Area of an equilateral triangle A =
/ 4
h = x / 2
Where,
x = Side
h = Height
Given that,
dA / dt = 5 / hr
h = x / 2
Differentiate both sides with respect to t
dh / dt = ( / 2 ) ( dx / dt )
dx / dt = ( 2 / ) ( dh / dt )
A =
/ 4
Differentiate both sides with respect to t
dA / dt = ( / 4 ) ( 2x ) ( dx / dt )
5 = ( / 4 ) ( 2x ) ( 2 /
) ( dh / dt )
dh / dt = ( 5 / x ) m / hr
Rate of change of height is defined as the rate at which height of an object changes with respect to time. It is represented as dh / dt
Therefore, the rate at which the height is changing is ( 5 / x ) m / hr
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