A conservative force is a force that when work is done against this force the work done does not depend on the path taken only the initial and final position.
Answer:
The magnitude of Force is 8.58×10⁵N and direction is upwards
Explanation:
The work beam does on the pile driver is given by
W=(FCos180°)Δx= -F(0.088m)
From work energy theorem
Choosing y=0 at the the level where the driver first contacts the beam and vi=0 at yi=+3.40m and comes to rest again vf=0 at yf= -0.088m
So
The magnitude of Force is 8.58×10⁵N and direction is upwards
Answer: well first you have to show or tell us the “error“ Selena made
Explanation:
Answer:
Length of the stake will be 0.3623 m
Explanation:
We have given energy required to fully drive a stake into ground = 0.30 KJ = 300 J
Average resistive force acting on the floor is equal to F = 828 N
We have to find the length of the stake
We know that work done is given by
W = Fd, here W is work done , F is average force and d is the length of the stake
So 300 = 828×d
d = 0.3623 m
So length of the stake will be 0.3623 m
consider the motion in vertical direction
v = initial velocity in the vertical direction = ?
v' = final velocity in the vertical direction at the highest point = 0 m/s
a = acceleration due to gravity = - 9.8 m/s²
h = maximum height = 12.2 m
Using the kinematics equation
v'² = v² + 2 a h
0² = v² + 2 (- 9.8) (12.2)
v = 15.5 m/s
let assume that velocity of launch be v₀
θ = angle of launch = 13
vertical component of the velocity of launch is given as
v = v₀ Sinθ
15.5 = v₀ Sin13
v₀ = 69 m/s
